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Alja [10]
3 years ago
11

The senior classes at High School A and High School B planned separate trips to the state fair. The senior class at High School

A rented and filled 10 vans and 6 buses with 276 students. High school B rented and filled 5 vans and 2 buses with 117 students. Every van had the same number of students in it as did the buses. How many students can a van carry? How many students can a bus carry?
Mathematics
1 answer:
Olenka [21]3 years ago
8 0
So from the situation you can set up a set of equation:

10v+6b=276
5v+2b=117

I will first solve for b
10v+4b=234
2b=42
Each bus holds 21 students.
5v+42=117
5v=75
v=25

In conclusion, each van holds 25 students and bus holds 21 students
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Marianna [84]
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If you are starting at point X and you walk to point Y, how many "lines" do you cross to get there?
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3 0
3 years ago
N - 4 = 3n + 6<br> Plz help me if possible no pics
levacccp [35]

Answer:

n=−5

Step-by-step explanation:

n−4−3n=3n+6−3n

−2n−4=6

Step 2: Add 4 to both sides.

−2n−4+4=6+4

−2n=10

Step 3: Divide both sides by -2.

−2n /−2 =  10 /−2

n=−5

4 0
2 years ago
Read 2 more answers
A 100-foot rope from the top of a tree house to the ground forms a 45∘ angle of elevation from the ground. How high is the top o
DochEvi [55]

Answer:

The height of tree house is 70.71 feet

Step-by-step explanation:

We are given that A 100-foot rope from the top of a tree house to the ground forms a 45∘ angle of elevation from the ground

Refer the attached figure

Length of rope AC = Hypotenuse =100 feet

The top of a tree house to the ground forms a 45∘ angle of elevation from the ground =\angle ACB = 45^{\circ}

We are supposed to find the height of tree house i.e.AB = Perpendicular

So, Using trigonometric ratio

Sin \theta = \frac{perpendicular}{Hypotenuse}\\Sin 45= \frac{AB}{AC}\\\frac{1}{\sqrt{2}}=\frac{AB}{100}\\100 \times \frac{1}{\sqrt{2}}=AB\\70.71=AB

Hence The height of tree house is 70.71 feet

8 0
3 years ago
Genius question: A long level railway bridge passes over a railroad track, which is 100 feet below it and at right angles to it.
nataly862011 [7]

Answer: <u>110 feet per second</u>

Step-by-step explanation:

In this problem we will assume that the car at 45 miles per hour is moving into the x direction with a high of 100 feet, and the train is going in the y direction, so they trajectories will made an angle of 90º.

Now we can calculate the speed of the trains in feet per second so:

S1=\frac{45*5280}{3600}=66

S2=\frac{60*5280}{3600}=88

So we can make a right triangle with sides 66 and 88 and the hypotenuse will be the rate that the trains will separate per second so:

h=\sqrt{66^{2} +88^{2} } =\sqrt{4356+7744}

h=\sqrt{12100}=110

Is important to have in mind that the initial high is not going to change how fast the trains will separate, however, if we are going to calculate the distance we should have it in the calculations.

7 0
2 years ago
Solve for v 17 - 2v = -53solve for v 17-2v=-53
lapo4ka [179]

Hey!

------------------------------------------------

Steps To Solve:

17 - 2v = -53

~Subtract 17 to both sides

17 - 2v - 17 = -53 - 17

~Simplify

-2v = -70

~Divide 2 to both sides

-2v/-2 = -70/-2

~Simplify

v = 35

------------------------------------------------

Hence, the answer is \Large\boxed{\mathsf{v~=~35}}

------------------------------------------------

Hope This Helped! Good Luck!

7 0
3 years ago
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