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Alja [10]
3 years ago
11

The senior classes at High School A and High School B planned separate trips to the state fair. The senior class at High School

A rented and filled 10 vans and 6 buses with 276 students. High school B rented and filled 5 vans and 2 buses with 117 students. Every van had the same number of students in it as did the buses. How many students can a van carry? How many students can a bus carry?
Mathematics
1 answer:
Olenka [21]3 years ago
8 0
So from the situation you can set up a set of equation:

10v+6b=276
5v+2b=117

I will first solve for b
10v+4b=234
2b=42
Each bus holds 21 students.
5v+42=117
5v=75
v=25

In conclusion, each van holds 25 students and bus holds 21 students
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$0.\overline{5} + 0.19\overline{4}$.
Scilla [17]

Answer:

0.\overline{5} + 0.19\overline{4}=0.75

Step-by-step explanation:

Given expression:

0.\overline{5} + 0.19\overline{4}

To evaluate the expression.

Solution.

The values are

0.\overline{5}=0.555555......  

Let X=0.555555..... -----------1                  

Multiplying 10 both sides.

10X=5.555555....----------2

Subtracting 1 from 2.

 10X=5.555555....

- X=0.555555.....

-------------------------------------------

9X=5.0

Dividing both sides by 9.

\frac{9X}{9}=\frac{5}{9}

X=\frac{5}{9}

0.19\overline{4}=0.194444....

Let Y=0.1944444..

Multiplying both sides by 100

100Y=19.44444..------------3

Multiplying 1000 both sides.

1000Y=194.4444....----------4

Subtracting 3 from 4.

 1000Y=194.4444....

- 100Y=19.44444.....

-------------------------------------------

900Y=175.0

Dividing both sides by 900.

\frac{900Y}{900}=\frac{175}{900}

Y=\frac{175}{900}

So, we can evaluate the given expression as:

⇒ 0.\overline{5} + 0.19\overline{4}

⇒ X+Y    

⇒ \frac{5}{9}+\frac{175}{900}

Taking LCD = 900

⇒ \frac{5\times 100}{9\times 100}+\frac{175}{900}

⇒ \frac{500}{900}+\frac{175}{900}

Adding numerators.

⇒ \frac{500+175}{900}

⇒ \frac{675}{900}

⇒ 0.75 (Answer)

7 0
3 years ago
Help pleaseee
Morgarella [4.7K]

Answer:

Step-by-step explanation:

     (x + 2)² = (x - 1)(x + 14)

x² + 4x + 4 = x² + 13x - 14

           -9x = -18

              x = 2

5 0
3 years ago
Help pleaseeeeeee quickly
shusha [124]

The first sentence in the chart belongs to the subjunctive mood, while the other sentences can be classified as part of the conditional mood.

<h3>What is a verb mood?</h3>

In language, the verb mood indicates the attitude of the speaker, and therefore, it provides clues about the way language is used. For example, the imperative mode indicates an order is being given.

<h3>What is the difference between the conditional and the subjunctive mood?</h3>
  • Subjunctive: It is used for expressing wishes; due to this, it is common to find the use of words such as "wish".
  • Conditional: It expresses a condition or a situation that will/can happen if another situation occurs. This can be identified due to the use of "if".

Based on this, the first sentences belongs to the subjunctive mood, while the other sentences are part of the conditional.

Learn more about the subjunctive in: brainly.com/question/22728240

#SPJ1

6 0
2 years ago
A group of 45 students went to a basketball game.
monitta

Answer:

See below. (C*a) + (P*b) = M

Step-by-step explanation:

amount of students = 45

amount of candy per student = 1

amount of popcorn per student = 1

Let "S" be the total amount of students

Let "C" be the total amount of candy

Let "P" be the total amount of popcorn

Let "T" be the total number of snacks

Let "a" be the price per candy

Let "b" be the price per popcorn

Let "M" be the total amount of money spent at the game

The price of the candy is unknown.

The price of the popcorn is unknown.

The total amount of money spent at the game is unknown.

(C*a) + (P*b) = M

I am not sure what you are asking for but, here is what I drew up for you. Hope this helps!

7 0
3 years ago
Find the exact value of sec theta if csc theta = -4/3 and the terminal side of theta lies in quadrant III
GREYUIT [131]

Answer:

-4 sqrt(7)/7

Step-by-step explanation:

csc theta = -4/3

csc theta = hypotenuse / opposite side

hypotenuse = 4  

opposite  = 3

Using the pythagorean theorem

a^2 + b^2 = c^2

3^2 + b^2 = 4^2

9+b^2 = 16

b^2 = 16-9

b^2 = 7

Taking the square root

sqrt(b^2) = sqrt(7)

b = sqrt(7)

We are in the third quadrant so only tan  and cot are positive

that means the x and y values are "negative"  so a = -3 and b = - sqrt(7)

sec theta = hypotenuse / adjacent

                = 4/ - sqrt(7)

rationalizing  

                   -4 sqrt(7)/ sqrt(7)* sqrt(7)

                = -4 sqrt(7)/7

           

3 0
3 years ago
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