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slega [8]
3 years ago
15

What is the change called from a liquid to a gas​

Chemistry
2 answers:
lana [24]3 years ago
8 0

Answer:

hmm I don't know but evaporation????

Sorry my spelling if off :<

P.S. please tell me if this is wrong

Explanation:

kenny6666 [7]3 years ago
3 0

Answer:

evaporation

Explanation:

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What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough
olga55 [171]

Answer:

Explanation:

molar mass of BaCl2 = 208.23

mol of BaCl2 = 8/208.22

mol of BaCl2 = 0.03841905

Molarity = 0.03841905/0.450

Molarity = 0.085 M

6 0
2 years ago
A chemist mixes 1.00 g CuCl2 with an excess of (NH4)2HPO4 in dilute aqueous solution . He measures the evolution of 670 J of hea
kaheart [24]

Answer:

\Delta H will be 90054 J

Explanation:

Number of moles = (mass)/(molar mass)

Molar mass of CuCl_{2} = 134.45 g/mol

So, 1.00 g of CuCl_{2} = \frac{1.00}{134.45}mol of CuCl_{2} = 0.00744 mol of CuCl_{2}

0.00744 mol of CuCl_{2} produces 670 J of heat

So, 1 mol of CuCl_{2} produces \frac{670}{0.00744}J of heat or 90054 J of heat

4 0
3 years ago
Can someone help me!
Art [367]

Answer:

A

Explanation:

5 0
3 years ago
Read 2 more answers
Rewrite the equation below using the correct conventions for stoichiometric coefficients. 2 BaCl2 + 2 H2SO4 → 2 BaSO4 + 4 HCl
vichka [17]

Answer:

BaCl2+H2SO4 \rightarrow BaSO4+2HCl

Explanation:

The given equation is:

2 BaCl2+2H2SO4 \rightarrow2BaSO4+4HCl

Based on the reaction stoichiometry:

2 moles of barium chloride (BaCl2) reacts with 2 moles of sulfuric acid (H2SO4) to form 2 moles of barium sulfate (BaSO4) and 4 moles of HCl

Although the reaction is balanced, the correct convention is to depict reactions in terms of the lowest molar ratio. Therefore the coefficients (2,2,4 and 4) can be divided by 2 to give:

BaCl2+H2SO4 \rightarrow BaSO4+2HCl

6 0
3 years ago
If the half life of a radioactive isotope is 5000 years, how much of the radioactive isotope in a specimen will be left after 10
marissa [1.9K]
Half life is the time taken by a radioactive isotope to decay by half its original mass. In this case, the halflife of the radioactive isotope is 5000 years. 
Initially the mass is 100 %; thus the mass that will be left will be given by;
New mass = Original mass × (1/2)^n where n is the number of half lives; 
  n = 10000/5000 = 2
New mass = 100% ×(1/2)^2
                 = 100 % × 1/4 
                 = 25%
Therefore; the mass left after 10000 years is 25% or 1/4 of the original mass.
5 0
3 years ago
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