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mina [271]
3 years ago
13

Jamie has a mass of 35kg what is her weight on earth in newtons

Physics
2 answers:
nevsk [136]3 years ago
8 0
Gravity on Earth = 10N/Kg
10N/Kg * 35Kg =350N
zvonat [6]3 years ago
3 0
On eart 1 kg is equal to 9.8 N/kg
So you just have to do 35•9,8= 343N
343 N is the answer.
And it is NOT 343 N/kg because the kilograms of 35 and the kilograms of 9,8 simplify (they cancel each other) so the remaining unit of measure is newton
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A simple harmonic oscillator oscillates with frequency f when its amplitude is
yKpoI14uk [10]
If the amplitude is doubled, the frequency is still f.

In fact, the frequency of a simple harmonic oscillator does not depend on the amplitude. The frequency of the oscillator in fact is:
f=  \frac{1}{2 \pi}  \sqrt{ \frac{k}{m} }
where
k is the spring constant
m is the mass attached to the spring

We can see that the frequency does not depend on the amplitude A, but only on the properties of the oscillator, so if the amplitude is doubled, the frequency does not change.
7 0
3 years ago
Your town is considering building a bio diesel power plant. Describe at least two advantages and two disadvantages of this proje
Pachacha [2.7K]

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6 0
3 years ago
When light strikes an object, what happens to some of the light?
svp [43]

Answer:

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5 0
3 years ago
To answer this question, suppose that each vehicle is moving at 7.69 m/s and that they undergo a perfectly inelastic head-on col
Maurinko [17]

Answer:

Force(F) = -80,955.01 N

Explanation:

We need to first determine the impulse that the truck driver received from the car during the collision

So; m₁v₁ - m₂v₂ = (m₁m₂)v₀

where;

m₁ = mass of the truck = 4280 kg

v₁ = v₂ =  speed of the each vehicle = 7.69 m/s

m₂ = mass of the car = 810 kg

Substituting our data; we have:

(4280×7.69) - (810×7.69) = (4280+810)v₀

32913.2 - 6228.9 = (5090)v₀

26684.1 =  (5090)v₀

v₀ = \frac{26684.1}{5090}

v₀ = 5.25 m/s

NOW, Impulse on the truck = m (v₀ - v)

= 4280 × (5.25 - 7.69)

= 4280 ×  (-2.44)

= -10,443.2 kg. m/s

Force that the seat belt exert on the truck driver can be calculated as:

Impulse = Force × Time

-10,443.2 kg. m/s = F (0.129)

F = \frac{-10,443.2}{0.129}

Force(F) = -80,955.01 N

Thus, the Force that the seat belt exert on the truck driver = -80,955.01 N

4 0
4 years ago
A steel ring is 50mm diameter and 2mm thick. it must be fitted onto a shaft 50.04 mm diameter. calculate the temperature to whic
MAVERICK [17]

The temperature to which it must be heated in order to fit the shaft is 73.33 ⁰C.

<h3>Linear expansivity </h3>

The temperature to which it must be heated in order to fit the shaft is calculated as follows;

\frac{\Delta L}{L} = \alpha \Delta T\\\\\Delta T = \frac{\Delta L}{\alpha L}

where;

  • ΔT is change in temperature
  • ΔL is change in length = 50.04 mm - 50 mm = 0.04 mm
  • α is coefficient of linear expansion
  • L is original length

ΔT = (0.04)/(50 x 15 x 10⁻⁶)

ΔT = 53.3 ⁰C

<h3>Final temperature</h3>

T₂ - T₁ = ΔT

T₂ = ΔT + T₁

where;

  • T₂ is final temperature
  • T₁ is initial temperature

T₂ = 53.3 + 20

T₂ = 73.33 ⁰C

Learn more about linear expansivity here: brainly.com/question/14325928

#SPJ1

4 0
2 years ago
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