What is the oxidation number of sulfur (S) in sulfuric acid (H2SO4)? -6 +2 +4 +6
2 answers:
Answer: Option (d) is the correct answer.
Explanation:
Oxidation number is defined as the number located at the top of the symbol of an atom by either gain or loss of electrons when it chemically combines with another atom.
In compound, the oxidation number of a hydrogen atom is +1 and oxidation number of an oxygen atom is -2.
Therefore, let the oxidation number of sulfur is x and calculate its value as follows.
2(1) + x + 4(-2) = 0
x = +6
Thus, we can conclude that the oxidation number of sulfur in sulfuric acid is +6.
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<u>Answer:</u> The formation of given amount of oxygen gas results in the absorption of 713 kJ of heat.
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
Given mass of oxygen gas = 83 g
Molar mass of oxygen gas = 32 g/mol
Putting values in above equation, we get:
For the given chemical equation:
<u>Sign convention of heat:</u>
When heat is absorbed, the sign of heat is taken to be positive and when heat is released, the sign of heat is taken to be negative.
By Stoichiometry of the reaction:
When 3 moles of oxygen gas is formed, the amount of heat absorbed is 824.2 kJ
So, when 2.594 moles of oxygen gas is formed, the amount of heat absorbed will be =
Hence, the formation of given amount of oxygen gas results in the absorption of 713 kJ of heat.