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photoshop1234 [79]
3 years ago
6

What evidence could an engineer use to construct an explanation about the energy of airplanes?Btw ( this is not part of question

) this is really science.
Engineering
1 answer:
il63 [147K]3 years ago
5 0

Explanation:

The following evidence could be used by an engineer;

The study of areodynamics and the fact that there are four parameters lift, weight, thrust and drag can explain the flying of airplanes in sky

Lift is a force that pushes the plane to rise ad it is actually the design of wings and their movements that create this lifting force

Weight is the force necessary to consider to make the plane fly and land

Then comes thrust, developed via engines or propellers of an airplane.

Last force is drag which defines the force needed to keep the plane pass through air.

A well calculated combination of all four forces actually make a plan fly

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The costs of mining and transporting coal are roughly independent of the heating value of the coal. Consider:
Paul [167]

Answer:

2

Explanation:

5 0
3 years ago
If the contact surface between the 20-kg block and the ground is smooth, determine the power of force F when t = 4 s. Initially,
grigory [225]

Answer:

The power of force F is 115.2 W

Explanation:

Use following formula

Power  = F x V

F_{H} = F cos0

F_{H} = (30) x 4/5

F_{H} = 24N

Now Calculate V using following formula

V = V_{0} + at

V_{0} = 0

a = F_{H} / m

a = 24N / 20 kg

a = 1.2m / S^{2}

no place value in the formula of V

V = 0 + (1.2)(4)

V = 4.8 m/s

So,

Power = F_{H} x V

Power = 24 x 4.8

Power = 115.2 W

3 0
3 years ago
Which of the following refers to a full-scale version of a product used to validate performance?
kompoz [17]
I’m thinking it would be c sorry if it’s wrong .
4 0
3 years ago
Read 2 more answers
Windmills slow the air and cause it to fill a larger channel as it passes through the blades. Consider a circular windmill with
Scilla [17]

Answer:

DIAMETER  = 9.797 m

POWER = \dot W = 28.6 kW

Explanation:

Given data:

circular windmill diamter D1 = 8m

v1 = 12 m/s

wind speed = 8 m/s

we know that specific volume is given as

v =\frac{RT}{P}

  where v is specific volume of air

considering air pressure is 100 kPa and temperature 20 degree celcius

v =  \frac{0.287\times 293}{100}

v = 0.8409 m^3/ kg

from continuity equation

A_1 V_1 = A_2 V_2

\frac{\pi}{4}D_1^2 V_1 = \frac{\pi}{4}D_1^2 V_2

D_2 = D_1 \sqrt{\frac{V_1}{V_2}}

D_2 = 8 \times \sqrt{\frac{12}{8}}

D_2 = 9.797 m

mass flow rate is given as

\dot m = \frac{A_1 V_1}{v} = \frac{\pi 8^2\times 12}{4\times 0.8049}

\dot m = 717.309 kg/s

the power produced \dot W = \dot m \frac{ V_1^2 - V_2^2}{2} = 717.3009 [\frac{12^2 - 8^2}{2} \times \frac{1 kJ/kg}{1000 m^2/s^2}]

\dot W = 28.6 kW

8 0
3 years ago
While discussing what affects the amount of pressure exerted by the brakes: Technician A says that the shorter the line, the mor
harina [27]

Answer:

Only Technician B is right.

Explanation:

The cylindrical braking system for a car works through the mode of pressure transmission, that is, the pressure applied to the brake pedals, is transmitted to the brake pad through the cylindrical piston.

Pressure applied on the pedal, P(pedal) = P(pad)

And the Pressure is the applied force/area for either pad or pedal. That is, P(pad) = Force(pad)/A(pad) & P(pedal) = F(pedal)/A(pedal)

If the area of piston increases, A(pad) increases and the P(pad) drops, Meaning, the pressure transmitted to the pad reduces. And for most cars, there's a pressure limit for the braking system to work.

If the A(pad) increases, P(pad) decreases and the braking force applied has to increase, to counter balance the dropping pressure and raise it.

This whole setup does not depend on the length of the braking lines; it only depends on the applied force and cross sectional Area (size) of the piston.

5 0
3 years ago
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