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mel-nik [20]
3 years ago
8

The sound intensity at a distance of 16 m from a noisy generator is measured to be 0.25 W/m2. What is the sound intensity at a d

istance of 28 m from the generator?
Physics
1 answer:
Margarita [4]3 years ago
4 0

Answer:

0.1111 W/m²

Explanation:

If all other parameters are constant, sound intensity is inversely proportional to the square of the distance of the sound. That is,

I ∝ (1/r²)

I = k/r²

Since k can be the constant of proportionality. k = Ir²

We can write this relation as

I₁ × r₁² = I₂ × r₂²

I₁ = 0.25 W/m²

r₁ = 16 m

I₂ = ?

r₂ = 24 m

0.25 × 16² = I₂ × 24²

I₂ = (0.25 × 16²)/24²

I₂ = 0.1111 W/m²

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Goshia [24]

Answer:

The velocity of the wave is 12.5 m/s

Explanation:

The given parameters are;

he frequency of the tuning fork, f = 250 Hz

The distance between successive crests of the wave formed, λ = 5 cm = 0.05 m

The velocity of a wave, v = f × λ

Where;

f = The frequency of the wave

λ = The wavelength of the wave - The distance between crests =

Substituting the known values gives;

v =  250 Hz × 0.05 m = 12.5 m/s

The velocity of the wave, v = 12.5 m/s.

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2 years ago
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The components that must be present for work to be considered is a force and a movement in the same direction as the force. In the basic definition of work, a magnitude and displacement that occurs in the same direction is what makes up work. Among the choices, the correct answer is the first one.
6 0
3 years ago
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A capacitance C and an inductance L are operated at the same angular frequency.
Levart [38]

A) \omega = \frac{1}{\sqrt{LC}}

The magnitude of the capacitive reactance is given by

X_C = \frac{1}{\omega C}

where

\omega is the angular frequency

C is the capacitance

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X_L = \omega L

where L is the inductance.

Since we want the two reactances to be equal, we have

X_C = X_L

So we find

\frac{1}{\omega C}= \omega L\\\omega^2 = \frac{1}{LC}\\\omega = \frac{1}{\sqrt{LC}}

B) 7449 rad/s

In this case, we have

L=5.30 mH = 5.3\cdot 10^{-3}H is the inductance

C= 3.40 \mu F= 3.40 \cdot 10^{-6}F is the capacitance

Therefore, substituting in the formula for the angular frequency, we find

\omega=\frac{1}{\sqrt{LC}}=\frac{1}{\sqrt{(5.30\cdot 10^{-3}H)(3.40\cdot 10^{-6} F)}}=7449 rad/s

C) 39.5 \Omega

Now we can us the formulas of the reactances written in part A). We have:

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X_C = \frac{1}{\omega C}=\frac{1}{(7449 rad/s)(3.40\cdot 10^{-6}F)}=39.5 \Omega

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7 0
3 years ago
If the line spectrum of lithium has a red line at 670.8 nm. How much energy does a a photon with this wavelength have?
Colt1911 [192]
We already know the formula for finding the energy of a photon with this wavelength as:
<span>E = ħc / λ
</span>The information's that we already know are:
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c = light speed
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</span><span>λ = Wavelength of the light as given in the question
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5 0
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Where does the atmosphere of the Earth end? (i.e. Where is the top of the Earth's atmosphere?) Where does the atmosphere of the
galben [10]

Answer:

b. There is no definite top to the atmosphere. The pressure and density gradually get smaller as the altitude gets larger.

Explanation:

There is no specific top of the atmosphere. It varies from place to place. But generally it is considered to be 480 kilometers thick.  But majority of its thickness is limited to 16 km only above earth surface. The pressure and density gradually get smaller as the altitude gets larger. The air pressure at sea level is 14.7 pounds per square inch and it decreases to 10 pounds per square inch at a height of 3 kilometers. From the above discussion we say that option B is correct

7 0
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