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Igoryamba
2 years ago
6

A school is creating a small parking lot next to the school. They will need

Physics
1 answer:
bagirrra123 [75]2 years ago
7 0

Answer:

2200.9lb

Explanation:

This is a conversion problem.

 We have been given that:

            Mass of rock the school needed  = 998140g

 

Unknown:

       Pound of rocks the park needed  = ?

To solve this problem, we have to convert from:

     grams to kilograms and then to pounds

            1000g of the rock will weigh 1kg

  So;       998140g of the rock will weight 998.14kg

Therefore:

               1kg of a substance weighs 2.205lb

           998.14g will weight2.205 x 998.14  = 2200.9lb

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Answer:

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A parallel-plate air capacitor is made from two plates 0.190 m square, spaced 0.770 cm apart. It is connected to a 120 V battery
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Answer:

aaksj

Explanation:

a) the capacitance is given of a plate capacitor is given by:

C = \epsilon_0*(A/d)

Where \epsilon_0 is a constant that represents the insulator between the plates (in this case air, \epsilon_0 = 8.84*10^(-12) F/m), A is the plate's area and d is the distance between the plates. So we have:

The plates are squares so their area is given by:

A = L^2 = 0.19^2 = 0.0361 m^2

C = 8.84*10^(-12)*(0.0361/0.0077) = 8.84*10^(-12) * 4.6883 = 41.444*10^(-12) F

b) The charge on the plates is given by the product of the capacitance by the voltage applied to it:

Q = C*V = 41.444*10^(-12)*120 = 4973.361 * 10^(-12) C = 4.973 * 10^(-9) C

c) The electric field on a capacitor is given by:

E = Q/(A*\epsilon_0) = [4.973*10^(-9)]/[0.0361*8.84*10^(-12)]

E = [4.973*10^(-9)]/[0.3191*10^(-12)] = 15.58*10^(3) V/m

d) The energy stored on the capacitor is given by:

W = 0.5*(C*V^2) = 0.5*[41.444*10^(-12) * (120)^2] = 298396.8*10^(-12) = 0.298 * 10 ^6 J

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