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2 years ago

Please help!! I'm stuck on this, could someone also explain if they can!! Will give brainiest if I can!!

Physics

1 answer:

Ann [662]2 years ago

8 0

The answer is going to be c. hope that helped

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At what displacement of a sho is the energy half kinetic and half potential? what fraction of the total energy of a sho is kinet

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As we know that KE and PE is same at a given position

so we will have as a function of position given as

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also the PE is given as function of position as

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now it is given that

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now we will have

$\frac{1}{2}m\omega^2(A^2 - x^2) = \frac{1}{2}m\omega^2x^2$

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Part b)

KE of SHO at x = A/3

we can use the formula

$KE = \frac{1}{2}m\omega^2(A^2 - x^2)$

now to find the fraction of kinetic energy

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$f_k = \frac{8}{9}$

now since total energy is sum of KE and PE

so fraction of PE at the same position will be

$f_{PE} = 1 - f_k$

$f_{PE} = 1 - (8/9) = 1/9$

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