Answer:
M₀ = 5i - 4j - k
Explanation:
Using the cross product method, the moment vector(M₀) of a force (F) is about a given point is equal to cross product of the vector A from the point (r) to anywhere on the line of action of the force itself. i.e
M₀ = r x F
From the question,
r = i + j + k
F = 1i + 0j +  5k
Therefore,
M₀ = (i + j + k) x (1i + 0j +  5k)
M₀ = ![\left[\begin{array}{ccc}i&j&k\\1&1&1\\1&0&5\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C1%261%261%5C%5C1%260%265%5Cend%7Barray%7D%5Cright%5D)
M₀ = i(5 - 0) -j(5 - 1) + k(0 - 1)
M₀ = i(5) - j(4) + k(-1)
M₀ = 5i - 4j - k
Therefore, the moment about the origin O of the force F is 
M₀ = 5i - 4j - k
 
        
             
        
        
        
A. it can be modified or rejected
        
             
        
        
        
His velocity is 3 m/s in the direction in which he is running in. which.
 
        
                    
             
        
        
        
Answer:

Explanation:
As we know that system of two boxes are moving on frictionless surface
So here if two boxes are considered as a system
then we have






Now since we know that both the boxes are moving together so force applied by first box on other box is given as



 
        
             
        
        
        
Answer:
90 meters
Explanation:
Given:
x₀ = 0 m
v₀ = 0 m/s
v = 30 m/s
t = 6 s
Find:
x
x = x₀ + ½ (v + v₀)t
x = 0 + ½ (30 + 0)(6)
x = 90
The car travels 90 meters.