in a circuit, where do electric charges go once they have left the voltage source and traveled along the wires?

1 answer:

7 0

In an electric circuit, the free electrons are moving around. Since equal charges repel and opposite charges attract, the electrons move from the negatively charged to the positively charged pole of the voltage source.

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An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. How high does it rise (v = 0 cm

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Answer:

The value of d is 20.4 m.

(C) is correct option.

Explanation:

Given that,

Initial velocity = 20 m/s

Final velocity = 0

We need to calculate the time

Using equation of motion

$v = u+gt$

Where, u = Initial velocity

v = Final velocity

Put the value into the formula

$t = \dfrac{20}{9.8}$

$t= 2.04\ sec$

We need to calculate the distance

Using equation of motion

$s = ut+\dfrac{1}{2}gt^2$

$s=0+\dfrac{1}{2}\times9.8\times(2.04)^2$

$s=20.4\ m$

Hence, The value of d is 20.4 m.

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