Answer:
The amplitude of the oscillation is 2.82 cm
Explanation:
Given;
mass of attached block, m = 4.1 kg
energy of the stretched spring, E = 3.8 J
period of oscillation, T = 0.13 s
First, determine the spring constant, k;
where;
T is the period oscillation
m is mass of the spring
k is the spring constant
Now, determine the amplitude of oscillation, A;
where;
E is the energy of the spring
k is the spring constant
A is the amplitude of the oscillation
Therefore, the amplitude of the oscillation is 2.82 cm
D is the best answer. In many physics problems we treat an extended object as if it were a point with the same mass located at the center of mass.
Answer:
A) Three hole punch and either a layered plastic or paper
B) Identify the lengths involved ,
Length of input arm / length of output arm = L1/ L2
Explanation:
<u>a) Materials involved includes :</u>
Three hole punch and either a layered plastic or paper
Identify the forces acting on the three-hole punch which are Input and output forces
Identify the points where they act
<u>B) procedures involved </u>
The mechanical advantage = output force / input force
step one: Identify the lengths involved
assuming no friction or relatively small friction \
mechanical advantage can be calculated as : Length of input arm / length of output arm = L1/ L2
Answer:
C.) Sled Team C 28 kg moving at 12m/s
I'm pretty sure.
Answer:
Would love to be your friend m'lady.
Explanation:
