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Kryger [21]
2 years ago
8

An areoplane initially at rest, undergoes a constant acceleration on of 2.5m/second down the runway for 30sec before taking off​

Physics
1 answer:
ikadub [295]2 years ago
4 0

Answer:

I'll just assume that the question is what's the velocity of the airplane before it takes off because you haven't included a question. Where u: velocity, a: acceleration, t: time

u = a \times t \\ u = 2.5 \times 30 \\ u = 70ms

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Explanation:

<h3>p = mv</h3>

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  • <em>v</em> denotes velocity

→ p = 3 kg × 3 m/s

→ <u>p</u><u> </u><u>=</u><u> </u><u>9</u><u> </u><u>kg</u><u>.</u><u>m</u><u>/</u><u>s</u>

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2 years ago
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<h2>Answer: C) It's a high-pressure zone with sinking air</h2>

Explanation:

The intertropical convergence zone is the region of the terrestrial globe where the trade winds of the northern hemisphere converge with those of the southern hemisphere.  

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Where does groundwater come from?
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Hope this helps.


Please mark as brainliest..........
4 0
2 years ago
Read 2 more answers
A 10.0-kg mass is placed on a 25.0o incline and friction keeps it from sliding. The coefficient of static friction in this case
vovangra [49]

The frictional force while the mass is sliding will be 46.2 N.

<h3>What is friction force?</h3>

Opposition forces on the surface cause heat loss during the motion of an object known as the friction force.

Given data:

m(mass)= 10.0-kg

Θ (Inclination angle)=25.0o

Coefficient of sliding friction,\rm \mu_k=0.520

Coefficient of static friction,\rm  \mu_s=0.520

The friction force, F=?

Resolve the force in the inclined plane;

\rm F=\mu_s mg cos25^0 \\\\ F=0.520 \times 10 \times 9.81 \times  cos 25 ^0 \\\\ F= 46.2 \ N

Hence, the frictional force while the mass is sliding will be 46.2 N.

To know more about friction force refer to the link;

brainly.com/question/1714663

#SPJ1

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John flies directly east for 20km, then turns to the north and flies for another 10 km before dodging a flock of geese. what’s t
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The distance is 30 km and the displacement is 22.4 km North East
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