Answer:
v = 15 m / s
Explanation:
In this exercise we are given the position function
x = 5 t²
and we are asked for the average velocity in an interval between t = 0 and t= 3 s, which is defined by the displacement between the time interval
let's look for the displacements
t = 0 x₀ = 0 m
t = 3
= 5 3 2
x_{f} = 45 m
we substitute

v = 15 m / s
Noble gasses ( insert gases)
Answer:
1 hour and 25 minutes
Explanation:
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