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SpyIntel [72]
3 years ago
12

Se realiza un experimento en el que se mide el alargamiento de un muelle debido a la acción de una pesa; se trata de comprobar l

a ley de Hooke. Los datos que se han obtenido son: Medición 1 2 3 4 5 Alargamiento 42.0 48.4 51.3 56.3 58.6 Masa 2 4 6 8 10 El coeficiente de determinación es:
Physics
1 answer:
mel-nik [20]3 years ago
4 0

Answer:

m = 1,975 m / kg , b = 38.05 m

Explanation:

In this experiment, the elongation is plotted against the applied mass

getting a straight line

            y = m x + b

 

where b would be the initial length of spring let's calculate the slope for which we use two well separated points

           m = (56.3 -48.4) / (8 - 4)

           m = 1,975 m / kg

the equation remains

         y = 1,975 x + b

for x = 2 kg y = 42.0 m

we substitute in the equation

           42 = 1,975 2 + b

           b = 42 - 3.95

           b = 38.05 m

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If you install special sound-reflecting windows that reduce the sound intensity level by 30.0 db , by what factor have you reduc
shusha [124]

Answer: The sound intensity was reduced by -14.77 dB.

Explanation:

The level of the intensity of the sound with respect to the reference value is called Sound Intensity level.

L_I=10\log\frac{I}{I_o} dB

I = Intensity of the sound

I_o = Reference sound intensity

According to question, sound-reflecting windows that reduce the sound intensity level by 30.0 db .

Let the intensity of the sound be I_o and reduced intensity be I.

I=\frac{I_o}{30} dB

L_I=10\log\frac{I}{I_o} dB

L_I=10\log\frac{\frac{I_o}{30}}{I_o}=10\log\frac{1}{30} dB=-14.77 dB

The sound intensity was reduced by -14.77 dB.

3 0
3 years ago
A 12-kg sled is moving at a speed of 2.0 m/s. At which of the following speeds will the sled have twice as much kinetic energy?
timama [110]

The answer you are looking for is A.

3 0
3 years ago
Read 2 more answers
Se deja resbalar por un plano inclinado de 30° un cuerpo de 15kg. Calcular la aceleración con la que desciende suponiendo que no
kupik [55]

Answer:

4.9 m/s^2

Explanation:

In order to find the acceleration of the block, we have to find the net force acting on it along the direction parallel to the incline.

However, there is only one force acting on the block along this direction: it is the component of the weight parallel to the plane, given by

mg sin \theta

where

m = 15 kg is the mass of the block

g=9.8 m/s^2 is the acceleration of gravity

\theta=30^{\circ} is the angle of the incline

According to Newton's second law, the net force is proportional to the acceleration, a:

F=ma

So we can write:

ma = mg sin \theta

And so, the acceleration is:

a=g sin \theta = (9.8)(sin 30^{\circ})=4.9 m/s^2

7 0
3 years ago
When a muscle is stretching by a contraction of the opposing muscle it is called
Sliva [168]
Try passive assistance if that will work, if not, <span> the definition would be a pilometric contraction.</span>
4 0
3 years ago
Give your answer in SI units and to three significant figures. A train departs Station A to travel to Station B which is 1188 me
Nikitich [7]

Answer:

Average velocity will be 58.181 m/sec      

Explanation:

Distance between station A and station B = 1188 meters

As the train starts from station A its initial velocity u = 0 m/sec

Final velocity is when it reaches at station B is 20 m/sec

Acceleration a=2.41m/sec^2

From first equation of motion v=u+at

20 = 0+2.41×t

t = 8.298 sec

Now from station train began to deaccelerate and finaly stop so final velocity v = 0 m /sec

Initial velocity u = 20 m/sec

We know that v = u+at

Deacceleration a=1.65m/sec^2

So 0 =20 -1.65×t

t = 12.12 sec

So total time = 8.298 + 12.12 = 20.419 sec

So average velocity =\frac{total\ distance}{total\ time}=\frac{1188}{20.419}=58.181m/sec

So average velocity will be 58.181 m/sec

5 0
3 years ago
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