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Firlakuza [10]
2 years ago
9

Amy spent $60 at the store

Mathematics
2 answers:
Margarita [4]2 years ago
6 0

Answer: 15

Step-by-step explanation: You do 60/4 to get the answer.

Karolina [17]2 years ago
3 0

Answer:

Step-by-step explanation:

if she spent $60 and 1/2 was on food she spents $30 on food and she has $30 left

if she spent 1/6 on soda than she spent $5 on soda and has $25 lef

if she spent 1/4 on school supplies and the remaining amount is $25 she spent $25 on school supplies

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solong [7]
She spent 5/6th of nights away from atlanta
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3 years ago
5n + 3 > 4 - (6 – 5n)
jek_recluse [69]
3>-2 i believe
djdjjdksksk sorry i needed more characters
4 0
3 years ago
Lee and Dan have the same number of blocks Lee has 20 green blocks and 36 blue blocks Dan has 13 green blocks 23 blue blocks and
Charra [1.4K]

Answer:

20 red blocks

Step-by-step explanation:

Lee blocks--20 + 36= 56

Dan blocks 13 + 23 =36  

56 - 36=20

8 0
3 years ago
Please help with this —
Igoryamba
3 times 8 is 24 and adding 7 is 31 so 31/1 divided by 19/1

U must flip the 19/1 to 1/19 and make it multiplication sign

31/1 times 1/19 is 31/19 or 1.63157
5 0
3 years ago
Read 2 more answers
Current research indicates that the distribution of the life expectancies of a certain protozoan is normal with a mean of 48 day
irina1246 [14]

Answer:

P ( x_bar ≥ 51 ) = 0.0432

Step-by-step explanation:

Solution:-

- The random variable "X" denotes:

                  X : life expectancies of a certain protozoan

- The variable "X" follows normal distribution.

                  X ~ Norm ( 48 , 10.5^2 )

- A sample of n = 36 days was taken.

- The sample is also modeled to be normally distributed:

                  x ~ Norm ( 48 , ( 10.5 / √n)^2 )

- The sample standard deviation s = 10.5 / √n = 10.5 / √36

                                                      s = 1.75

- We are to investigate the the probability of sample mean x_bar ≥ 51 days:

                 P ( x_bar ≥ 51 )

- Standardize the results, evaluate Z-score:

                 P ( Z ≥ ( x_bar - u ) / s ) =  P ( Z ≥ ( 51 - 48 ) / 1.75 )

                 P ( Z ≥ 1.7142 ).

- Use the standardized normal table and evaluate:

                 P ( Z ≥ 1.7142 ) = 0.0432                  

Hence,      P ( x_bar ≥ 51 ) = 0.0432

5 0
3 years ago
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