Answer:
17.09 Ω
Explanation:
First we find the voltage induced in the coil, using
E = NdΦ/dt........................... Equation 1
Where E = Induced voltage, N = Number of turns, dΦ = change in magnetic flux, dt = change in time/ Time interval
Give: N = 22 turns, dΦ = 13-2.5 = 10.5 Wb, dt = 0.052 s.
Substitute into equation 1
E = 22(10.5)/0.052
E = 4442.31 V.
Using Ohm's Law,
E = IR......................... Equation 2
Where I = current, R = Resistance of the wire, E = Voltage.
make R the subject of the equation,
R = E/I................. Equation 3
Give: I = 260 A, E = 4442.31 V
Substitute into equation 3
R = 4442.31/260
R = 17.09 Ω
