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RSB [31]
3 years ago
7

density of a sample of tin is 8 g/'ll when the actual density was 7.28 g/ml. what was the percentage error

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
7 0

9.9%

|Approximate Value − Exact Value| divided by

|Exact Value| X 100

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When a 0. 1 m aqueous solution of hydrocyanic acid, hcn, reaches equilibrium, the ph is measured to be 5. 20. using this informa
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When a 0. 1 m aqueous solution of hydrocyanic acid, HCN, reaches equilibrium, the ka for hydrocyanic acid is  3.969 x 10⁻¹⁰.

<h3>What is ka value?</h3>

It's the value of equilibrium constant for the dissociation of ions into a solution. The more the Ka value the more will be dissociation.

Ka = [H₃O⁺]² / [HCN] [H₃O⁺]

The pH is 5.20

-log [H₃O⁺] = 5.20

Putting antitlog both side.

The value will be 6.30 x 10⁻⁶

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Thus, the Ka value for hydrocyanic acid is 3.969 x 10⁻¹⁰.

To learn more about ka value, refer to the link:

brainly.com/question/2796803

#SPJ4

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