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RSB [31]
3 years ago
7

density of a sample of tin is 8 g/'ll when the actual density was 7.28 g/ml. what was the percentage error

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
7 0

9.9%

|Approximate Value − Exact Value| divided by

|Exact Value| X 100

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In a varve, summer is represented by _____.
Tasya [4]

Answer:

sediment from melting glaciers being deposited in lakes

Explanation:

I took the test

5 0
2 years ago
Given the following information:Br2 bond energy = 193 kJ/mol F2 bond energy = 154 kJ/mol 1/2Br2(g) + 3/2F2(g) -> BrF3(g) = –3
arlik [135]

Answer:

C) 712 KJ/mol

Explanation:

  • ΔH°r = Σ Eb broken - Σ Eb formed
  • 1/2Br2(g) + 3/2F2(g) → BrF3(g)

∴ ΔH°r = - 384 KJ/mol

∴ Br2 Eb = 193 KJ/mol

∴ F2 Eb = 154 KJ/mol

⇒ Σ Eb broken = (1/2)(Br-Br) + (3/2)(F-F)

⇒ Σ Eb broken =  (1/2)(193 KJ/mol) + (3/2)(154 KJ/mol) = 327.5 KJ/mol

∴ Eb formed: Br-F

⇒ Σ Eb formed (Br-F) = Σ Eb broken - ΔH°r

⇒ Eb (Br-F) = 327.5 KJ/mol - ( - 384 KJ/mol )

⇒ Eb Br-F = 327.5 KJ/mol + 384 KJ/mol = 711.5 KJ/mol ≅ 712 KJ/mol

8 0
3 years ago
Kinetic energy definition
igomit [66]

Answer:

kinetic energy. (General Physics) the energy of motion of a body, equal to the work it would do if it were brought to rest. The translational kinetic energy depends on motion through space, and for a rigid body of constant mass is equal to the product of half the mass times the square of the speed.

5 0
3 years ago
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Consider the malate dehydrogenase reaction from the citric acid cycle. Given the listed concentrations, calculate the free energ
Ahat [919]

<u>Answer:</u> The Gibbs free energy of the reaction is 21.32 kJ/mol

<u>Explanation:</u>

The chemical equation follows:

\text{Malate }+NAD^+\rightleftharpoons \text{Oxaloacetate }+NADH

The equation used to Gibbs free energy of the reaction follows:

\Delta G=\Delta G^o+RT\ln K_{eq}

where,

\Delta G = free energy of the reaction

\Delta G^o = standard Gibbs free energy = 29.7 kJ/mol = 29700 J/mol  (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314J/K mol

T = Temperature = 37^oC=[273+37]K=310K

K_{eq} = Ratio of concentration of products and reactants = \frac{\text{[Oxaloacetate]}[NADH]}{\text{[Malate]}[NAD^+]}

\text{[Oxaloacetate]}=0.130mM

[NADH]=2.0\times 10^2mM

\text{[Malate]}=1.37mM

[NAD^+]=490mM

Putting values in above expression, we get:

\Delta G=29700J/mol+(8.314J/K.mol\times 310K\times \ln (\frac{0.130\times 2.0\times 10^2}{1.37\times 490}))\\\\\Delta G=21320.7J/mol=21.32kJ/mol

Hence, the Gibbs free energy of the reaction is 21.32 kJ/mol

4 0
3 years ago
I NEED THIS FAST PLZ!!!<br><br> CAN U GUYS HELP ME ANSWER ANY OF THESE QUESTIONS
liubo4ka [24]

Answer:

Pascal is the most common unit for measuring pressure

The average sea level pressure is 1013 mbar

4 0
3 years ago
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