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bonufazy [111]
3 years ago
5

A piece of silver of volume 10cm has a massof 103g . Find its Density.​

Physics
1 answer:
klemol [59]3 years ago
3 0

Answer:

d=10.3g/cm³

Explanation:

density is defined as the ratio of mass of an object to its mass volume.

d= m/V

Substitute the values given in the problem

d=(103g)/(10cm³)

d=10.3g/cm³

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Write with all the steps and formulas and drawing if needed.​
lianna [129]

<u>The answer is not contained detail explanation, just a solution and the required values. </u>

All the details are in the pictures, the answers are marked with orange colour.

Note,

in the task no 20.:

m_A - the \ mass \ of \ A; \ m_B-the \ mass \ of \ B \ balls.\\V_A \ and \ V_B-the \ velocities \ of \ the \ A&B \ balls \ before \ collision.\\V'_A \ and \ V'_B-the \ velocities \ of \ the \ A&B \ balls \ after \ collision.

V - the velocity of the pair of the balls after collision.

in the task no 21:

m₁ - the mass of the copper ball; m₂ - the mass of the copper calorimeter; m₃ - the mass of the water; t₀ - the initial temperature of water in the copper calorimeter; θ - the final temperature in the calorimeter after the copper ball is transferred into a copper calorimeter; t₁ - the required initial temperature of the copper ball before it is transferred into the calorimeter.

7 0
3 years ago
Does the apple scatter red light​
Mkey [24]

Answer: No

Explanation: colour of substance appears when molecules of apple

Absorb wavelengths of counter colour, also green light.

Counter colours are green-red, violet -yellow and blue-orange

6 0
2 years ago
A weight lifter lifts a 1.0 x 102 kg mass 1.5 m in 2.0 s. The power is?
Serga [27]

Answer:

\boxed{p =  {7.4 \times 10}^{2} W} \to \: option \: c.

Explanation:

his \: power \: is \to \\ p =  \frac{mgh}{t}  \\ p =  \frac{1.0 { \times 10}^{2}  \times 1.5 \times 9.8}{2.0}   \\  p= 735 \\  \boxed{p =  {7.4 \times 10}^{2} }

6 0
2 years ago
A planet has a period of revolution about the sun equal to T and a mean distance from the sun equal to R. T2 varies directly as
Tamiku [17]

Answer:

T² ∝ R³

Explanation:

Given data,

The period of revolution of the planet around the sun, T

The mean distance of the planet from the sun, R

According to the III law of Kepler, " Law of Periods' states that the square of the orbital period to go around the sun once is directly proportional to the cube of the mean distance between the sun and the planet.

                              T² ∝ R³

                               \frac{T^{2}}{R^{3}} = Constant

From the above equation it is clear that T² varies directly as the R³.

7 0
3 years ago
True or False: There is no object that can travel faster than the speed of light.
Otrada [13]
True no object can travel faster than speed of light
6 0
2 years ago
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