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Blababa [14]
3 years ago
14

3. Why is static electricity not useful as a power

Physics
1 answer:
shtirl [24]3 years ago
3 0
The answer is B, because all energy is released at once in static electricity.

There’s a quizlet that mentions these questions, if you are having trouble. I’d suggest to give them a look.
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Can anyone answer my questions that I've asked?
Monica [59]

Answer:

76 N north-east

Explanation:

V = √(44²+62²) = 76 N

8 0
3 years ago
An electric toaster is rated 1200 watts at 120 volts. what is the total electrical energy used to operate the toaster for 30 sec
Tresset [83]

Answer : Total electrical energy is 36000 J.

Explanation :

It is given that,

Power of electric toaster, P = 1200 Watts

Voltage, V = 120 Volts

Time, t = 30 s

Electric energy is defined as the product of the power and the time taken.

E=Pt

E=1200\ W\times 30\ s

E=36000\ J

Total electrical energy used to operate the toaster for 30 seconds is 36000 J.

8 0
4 years ago
Read 2 more answers
which of these changes does a submarine encounter as it returns from the bottom of the ocean to the surface of the ocean? a. the
Lady bird [3.3K]
The amount of sunlight increases 
4 0
3 years ago
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Electric charge is distributed over the disk x2 + y2 ≤ 4 so that the charge density at (x, y) is rho(x, y) = 4x + 4y + 4x2 + 4y2
maw [93]

Answer:

Q=185.84C

Explanation:

We have to take into account the integral

Q=\int \rho dV

In this case we have a superficial density in coordinate system.

Hence, we have for R: x2 + y2 ≤ 4

Q=\int_{-2}^2\int_{-\sqrt{4-x^2}}^{\sqrt{4-x^2}}\rho dydx

but, for symmetry:

Q=4\int_0^2\int_0^{\sqrt{4-x^2}}\rho dydx\\\\Q=4\int_0^2\int_0^{\sqrt{4-x^2}}(4x+4y+4x^2+4y^2) dydx\\\\Q=4\int_0^{2}[4x\sqrt{4-x^2}+2(4-x^2)+4x^2\sqrt{4-x^2}+\frac{4}{3}(4-x^2)^{3/2}]dx\\\\Q=4[46.46]=185.84C

HOPE THIS HELPS!!

8 0
3 years ago
To what extent are disorders the product of a particular environment, and to what extent
mixas84 [53]
Sorry don’t know hope you gave the answer to your questions
8 0
3 years ago
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