2 years ago

1. Which will speed up the rate of a chemical

1 answer:

8 0

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Khi phân cực thuận Diode có dòng điện chạy theo chiều

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A.từ A về K
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2 years ago

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3 years ago

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A 200-g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. The total energy

m_a_m_a [10]

Answer:

(A) Spring constant will be 126.58 N/m

(B) Amplitude will be equal to 0.177 m

Explanation:

We have given mass of the block m = 200 gram = 0.2 kg

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Total energy is given TE = 2 J

(A) For mass spring system time period is equal to $T=2\pi \sqrt{\frac{m}{K}}$

So $0.250=2\times 3.14 \sqrt{\frac{0.2}{K}}$

$0.0398=\sqrt{\frac{0.2}{K}}$

Now squaring both side

$0.00158=\frac{0.2}{K}$

K = 126.58 N/m

So the spring constant of the spring will be 126.58 N/m

(B) Total energy is equal to $TE=\frac{1}{2}KA^2$ , here K is spring constant and A is amplitude

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$A^2=0.0316$

A = 0.177 m

So the amplitude of the wave will be equal to 0.177 m

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3 years ago

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