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mel-nik [20]
3 years ago
7

Why can't we implement the center tapped full wave rectifier without center-tapped transformer

Physics
1 answer:
maksim [4K]3 years ago
6 0
For a full wave bridge you don't want a center tap
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What will police do with witnesses at the scene?
NNADVOKAT [17]

Answer:

Speaking to witnesses is a job they do. If anyone stops after seeing the accident occur, the officers who respond to the accident take their personal information, they get their contact information, and they add their statements to their report.

Explanation:

4 0
3 years ago
Read 2 more answers
A gray kangaroo can bound across level ground with each jump carrying it 9.6 m from the takeoff point. Typically the kangaroo le
xz_007 [3.2K]

Answer:

(A) 11 m/s

(B) 1.3 m

Explanation:

Horizontal range, R = 9.6 m

Angle of projection, theta = 28 degree

(A)

Use the formula of horizontal range

R = u^2 Sin 2 theta / g

u^2 = R g / Sin 2 theta

u^2 = 9.6 × 9.8 / Sin ( 2 × 28)

u = 10.65 m/s

u = 11 m/s

(B)

Use the formula for maximum height

H = u^2 Sin ^2 theta / 2g

H =

10.65 × 10.65 × Sin^2 (28) / ( 2 × 9.8)

H = 1.275 m

H = 1 .3 m

4 0
3 years ago
A block slides down a frictionless inclined ramp. If the ramp angle is 17.0° and its length is 30.0 m, find the speed of the blo
shutvik [7]

Answer:

 v = 17.15 m/s

Explanation:

given,

angle of ramp = 17.0°

length of ramp(l) = 30 m

height of the ramp =  

     h = l sin \theta

     h = 30 sin 30^0

            h = 15 m

using energy of conservation

\dfrac{1}{2}mv^2 = mgh

\dfrac{1}{2}v^2 = gh

v = \sqrt{2gh}

v = \sqrt{2\times 9.8\times 15}

v = \sqrt{294}

 v = 17.15 m/s

 speed of block reaching at the bottom = v = 17.15 m/s

5 0
3 years ago
A 65 N boy sits on a sled weighing 52 N on a horizontal surface. The coefficient of friction between the sled and the snow is 0.
pogonyaev

Answer:

1.40 N

Explanation:

The magnitude of the frictional force is given by:

F=\mu N

where

\mu is the coefficient of friction

N is the magnitude of the normal reaction

The coefficient of friction for this problem is \mu=0.012. The magnitude of the normal reaction is equal to the combined weight of the boy and the sled, because the surface is horizontal, so

N=65 N+52 N=117 N

Therefore, the frictional force is

F=\mu N=(0.012)(117 N)=1.40 N

3 0
3 years ago
A car is driven 125.0 km due west then 65.0 km due south. What is the magnitude of its displacement?
kodGreya [7K]

pythagoras' theorem on right angled triangle. sides 125, 65

sqrt (125^2 +65^2)

5 0
3 years ago
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