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SashulF [63]
3 years ago
12

Identify the nuclide that would be formed from the alpha particle emission of Fm-257.

Chemistry
1 answer:
Elodia [21]3 years ago
5 0

Answer: 1) The nuclide formed from the alpha decay of _{100}^{257}\textrm{Fm} is _{98}^{253}\textrm{Cf}

2) The nuclide formed from the beta-minus decay of _{98}^{253}\textrm{Cf} is _{99}^{253}\textrm{Es}

Explanation:

1) For alpha-decay

In this process, alpha particle is released.

Equation follows:

_{100}^{257}\textrm{Fm}\rightarrow _{98}^{253}\textrm{Cf}+_2^4\alpha

The nuclide formed is _{98}^{253}\textrm{Cf}

2) For beta-minus decay

In this process, a neutron is converted into a proton and an electron.

Equation follows:

_{98}^{253}\textrm{Cf}\rightarrow _{99}^{253}\textrm{Es}+_{-1}^0\beta

The nuclide formed is _{99}^{253}\textrm{Es}

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D. has different properties when sampled in different areas.

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Such as a mixture of oil and water is a heterogeneous mixture and have different properties or different densities, which helps them to be sampled in different areas.

Hence, the correct answer is "D".

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How many mL of a stock 50% (w/v) KNO3 solution are needed to prepare 250 mL of a 20% (w/v) KNO3 solution?
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Answer:

100ml of a stock 50% KNO3 solutions are needed to prepare 250ml of a 20% KNO3 solution.

Explanation:

In the given question it is mentioned that

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We all know that

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                     ∴V1=  V2×S2÷S1

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