Question

Identify the nuclide that would be formed from the alpha particle emission of Fm-257.

Answer 1

Answer: 1) The nuclide formed from the alpha decay of $_{100}^{257}\textrm{Fm}$ is $_{98}^{253}\textrm{Cf}$

2) The nuclide formed from the beta-minus decay of $_{98}^{253}\textrm{Cf}$ is $_{99}^{253}\textrm{Es}$

Explanation:

1) For alpha-decay

In this process, alpha particle is released.

Equation follows:

$_{100}^{257}\textrm{Fm}\rightarrow _{98}^{253}\textrm{Cf}+_2^4\alpha$

The nuclide formed is $_{98}^{253}\textrm{Cf}$

2) For beta-minus decay

In this process, a neutron is converted into a proton and an electron.

Equation follows:

$_{98}^{253}\textrm{Cf}\rightarrow _{99}^{253}\textrm{Es}+_{-1}^0\beta$

The nuclide formed is $_{99}^{253}\textrm{Es}$