A circuit consists of a conducting movable bar and a lightbulb connected to two conducting rails as shown in the figure below. A
n external magnetic field is directed perpendicular to the plane of the circuit. Which of the following actions will make the bulb light up? (Select all that apply.)
The bar is moved to the left.
The bar is moved to the right.
The magnitude of the magnetic field is increased.
The magnitude of the magnetic field is decreased.
The bar is lifted off the rails.
The bar is moved to the left.
The bar is moved to the right.
The magnitude of the magnetic field is increased.
The magnitude of the magnetic field is decreased.
The bar is lifted off the rails.
1 answer:
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To solve this problem we must resort to the Work Theorem, internal energy and Heat transfer. Summarized in the first law of thermodynamics.
Where,
Q = Heat
U = Internal Energy
By reference system and nomenclature we know that the work done ON the system is taken negative and the heat extracted is also considered negative, therefore
Work is done ON the system
Heat is extracted FROM the system
Therefore the value of the Work done on the system is -158.0J