600Hz is the driving frequency needed to create a standing wave with five equal segments.
To find the answer, we have to know about the fundamental frequency.
<h3>How to find the driving frequency?</h3>
- The following expression can be used to relate the fundamental frequency to the driving frequency;
f(n) = n * f (1)
where, f(1) denotes the fundamental frequency and the driving frequency f(n).
- The standing wave has four equal segments, hence with n=4 and f(n)=4, we may calculate the fundamental frequency.
f(4) = 4× f (1)
480 = 4× f(1)
f(1) = 480/4 =120Hz.
So, 120Hz is the fundamental frequency.
- To determine the driving frequency necessary to create a standing wave with five equally spaced peaks?
- For, n = 5,
f(n) = n 120Hz,
f(5) = 5×120Hz=600Hz.
Consequently, 600Hz is the driving frequency needed to create a standing wave with five equal segments.
Learn more about the fundamental frequency here:
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Answer:
To find the diameter of the wire, when the following are given:
Resistivity of the material (Rho), Current flowing in the conductor, I, Potential difference across the conductor ends, V, and length of the wire/conductor, L.
Using the ohm's law,
Resistance R = (rho*L)/A
R = V/I.
Crossectional area of the wire A = π*square of radius
Radius = sqrt(A/π)
Diameter = Radius/2 = [sqrt(A/π)]
Making A the subject of the formular
A = (rho* L* I)V.
From the result of A, Diameter can be determined using
Diameter = [sqrt(A/π)]/2. π is a constant with the value 22/7
Explanation:
Error and uncertainty can be measured varying the value of the parameters used and calculating different values of the diameters. Compare the values using standard deviation
Answer
Force will be 1520.2604 N
Explanation:
We have given mass of the bullet m = 10.1 gram = 0.0101 kg
Distance S= 0.6 m
Final velocity v = 425 m/sec
Initial velocity u will be 0 m/sec
From third equation of motion 
We know that force is given by F = ma
So force = 0.0101×150520.833 = 1520.2604 N
Answer:
Acceleration of the boy a₁:
Explanation:
Conceptual analysis
We apply Newton's second law to the boy and the girl:
F = m*a (Formula 1)
F : Force in Newtons (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Nomenclature
m₁ : boy mass
m₂ : girl mass
a₁ : boy acceleration
a₂ : girl acceleration
F₁ : boy acceleration
F₂ : girl acceleration
Known data
m₁ = 57 kg
m₂ = 41 kg
a₂ = 2.6 m/s²
Problem development
We apply to Newton's third law of action and reaction, then:
F₁ = F₂ , We apply the formula (1):
m₁*a₁ = m₂*a₂
