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Bond [772]
3 years ago
13

How do you figure out escape velocity

Physics
1 answer:
Gnesinka [82]3 years ago
6 0

Equation

KE. + PE. = KE<em>f </em>+ PE<em>f</em>

<em>By the time the Rocket reaches an infinete distance the </em><em>KE</em><em>f and </em><em>PE</em><em>f  power would be down to zero so then the equation will become </em><em>KE. + PE. = 0 </em>

<em>Cant explain much because dont know if this anserw recwires any speical things to solve it</em>





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Question 30
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Answer: 0.69\°

Explanation:

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\delta=2 sin^{-1}(\frac{d}{2D})

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Hence:

\delta=2 sin^{-1}(\frac{16 m}{2(1338 m)})

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Determine the vector perpendicular to the plane of A= 31+ 6j - 2k and B=4i-j +3k
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The vector perpendicular to the plane of A = 3i+ 6j - 2k and B = 4i-j +3k is 16 i - 17 j - 27 k

Let r be the vector perpendicular to A and B,

r = A * B

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a1 = 3

a2 = 6

a3 = - 2

b1 = 4

b2 = - 1

b3 = 3

a * b = ( a2 b3 - b2 a3 ) i + ( a3 b1 - b3 a1 ) j + ( a1 b2 - b1 a2 ) k

a * b = [ ( 6 * 3 ) - ( - 1 * - 2 ) ] i + [ ( - 2 * 4 ) - ( 3 * 3 ) ] j + [ ( 3 * - 1 ) - ( 4 * 6 ) ] k

a * b = 16 i - 17 j - 27 k

The perpendicular vector, r = 16 i - 17 j - 27 k

Therefore, the vector perpendicular to the plane of A = 3i + 6j - 2k and B = 4i - j + 3k is 16 i - 17 j - 27 k

To know more about perpendicular vectors

brainly.com/question/14384780

#SPJ1

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The band gab of semi conductor?
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