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3 years ago

What is the main pigement for photosyenthesis inchloroplasts

Chemistry

1 answer:

Ilya [14]3 years ago

3 0

I assume the answer is chlorophyll (a or b) but could also be carotenoids.

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What two aspects of a force do scientists measure?

soldier1979 [14.2K]

Yo sup??

Force is a vector quantity therefore it has both direction and magnitude.

Hence scientists measure magnitude and direction of a force.

Correct answer is option A

Hope this helps

5 0

3 years ago

Select the correct answer.

frozen [14]

Answer:

1.79x10^-14

Explanation:

pOH + pH = 14

H+=10^-pH

- Hope that helps! Please let me know if you need further explanation.

3 0

3 years ago

A series circuit has two 5.0-ohm resistors and a power source of 9.0 volts. How will the current be affected and what will it be

miskamm [114]

The formula for solving current given with resistance and power source or voltage is shown below:
I = V/R

When two 5 ohms resistors are in series, we have:
I = 9 volts / (5+5 ohms)
I = 0.9 amperes

When it is being added with another 7.5 resistors, we have:
I = 9 volts / (5+5+7.5 ohms)
I = 0.529 ampere

The answer to the question is the letter "D. decrease; 0.51 amps".

3 0

3 years ago

What is the energy of a moving mass?

satela [25.4K]

Answer:

Kinetic energy

Explanation:

This is the energy possessed by a moving object.

6 0

3 years ago

A volume of 105 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If

NemiM [27]

Answer:

<h3>25.0 grams is the mass of the steel bar.</h3>

Explanation:

Heat gained by steel bar will be equal to heat lost by the water

$Q_1=-Q_2$

Mass of steel= $m_1$

Specific heat capacity of steel = $c_1=0.452 J/g^oC$

Initial temperature of the steel = $T_1=2.00^oC$

Final temperature of the steel = $T_2=T=21.50^oC$

$Q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2= 105 g$

Specific heat capacity of water= $c_2=4.18 J/g^oC$

Initial temperature of the water = $T_3=22.00^oC$

Final temperature of water = $T_2=T=21.50^oC$

$Q_2=m_2c_2\times (T-T_3)-Q_1=Q_2(m_1c_1\times (T-T_1))=-(m_2c_2\times (T-T_3))$

On substituting all values:

$(m_1\times 0.452 J/g^oC\times (21.50^o-2.00^oC))=-(105 g\times 4.18 J/g^oC\times (21.50^o-22.00^o))\\\\m_1*8.7914=241.395\\\\m_1=\frac{219.45}{8.7914} \\\\m_1=24.9\\\\ \approx25 \texttt {grams}$

<h3>25.0 grams is the mass of the steel bar.</h3>

3 0

3 years ago

Read 2 more answers