Answer:
The answer is
<h2>11.73 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass of object = 30.5 g
Density = 2.6 g/cm³
The volume is
We have the final answer as
<h3>11.73 mL</h3>
Hope this helps you
The symbol of the period five element that is a member of the pnicitides family are antimony.
Explanation:
Pnictogen family
- In periodic table, column 15 elements are Pnitogen family.
- The pnictogen elements are Nitrogen-N, arsenic-As, phosphorus-P, bismuth-Bi, antimony-Sb, ununpentium-Uup.
- There are five valence electrons each member of pnictogen family. In group 15 double bonds and triple bonds are formed due to these valence electrons.
- Pnictides, binary compounds of group 15.
Antimony
- Antimony is the element found in period 5 and block p.
- A chemical element, Antimony (Sb) from Latin word stibium and 51 is its atomic number. It is in solid state.
- In ancient times, antimony compounds are used as cosmetic and medicine.
- Appeared as semi metal.
- Electronic configurations of Sb is [Kr] 4d105s25p3.
Based on location in the periodic table, fluorine (F) has chemical properties that are most similar to iodine.
In the periodic table, elements are classified in groups and periods. The elements in the same group are chemically similar and they have the same number of valence electrons. Elements in the same period have the same highest energy level.
Hence, when looking for an element that is most chemically similar to iodine, we have to consider the element that is in the same group with iodine.
Both fluorine are iodine are both in group 17 hence, fluorine is most chemically similar to iodine.
Learn more: brainly.com/question/11155928
Answer:
Explanation:
Initial burette reading = 1.81 mL
final burette reading = 39.7 mL
volume of NaOH used = 39.7 - 1.81 = 37.89 mL .
37.89 mL of .1029 M NaOH is used to neutralise triprotic acid
No of moles contained by 37.89 mL of .1029 M NaOH
= .03789 x .1029 moles
= 3.89 x 10⁻³ moles
Since acid is triprotic , its equivalent weight = molecular weight / 3
No of moles of triprotic acid = 3.89 x 10⁻³ / 3
= 1.30 x 10⁻³ moles .
