Answer:
It’s cool I’d say 8/10 I guess
Explanation:
Answer:
a) 18.75 ft^2
b) 2.5 ft
c) 12.07 ft
d) 10 ft
e) 1.553 ft
f) 1.875 ft
Explanation:
Given data :
5.0-ft bed width, ( b )
2.5-ft depth ( y )
1 : 1 side slope
Evaluate
a) Area of trapezoidal section
A = by + my^2
we assume m = 1
A = [5 + (1 * 2.5 ) ] *2.5
= ( 7.5 ) 2.5 = 18.75 ft^2
b) Calculate water depth
water depth = 2.5 ft
c) Calculate wetted perimeter
P = b + 2y √ 1 + m^2
= 5 + (2.5*2) √ 1 + 1 ^2 = 12.07 ft
d) calculate top width
T = b + 2my
= 5 + 2 ( 1 * 2.5 ) = 10 ft
e) calculate hydraulic radius
R = A / P = 18.75 / 12.07
= 1.553 ft
f) calculate hydraulic depth
D = A / T = 18.75 / 10 = 1.875 ft
Answer:
factor of safety = 0.8
Explanation:
given data
maximum gauge pressure in steel p = 10 MPa
outer diameter do = 200 mm
wall thickness t = 2 mm
ultimate stress of the steel σU = 400 MPa
solution
We check the type of shell that is
so we can see that that is
so that it mean vessel is a thin shell now we can we get maximum pressure by the maximum tensile stress is
σ =
.......................1
put here value and we get
σ =
σ = 500 MPa
so factor of safety will be express as
factor of safety =
..........2
factor of safety =
factor of safety = 0.8
Answer
given,
P₁ = 10 MPa T₁ = 800
P₂ = 800 KPa T₂ = ?
Using formula

For steam n = 1.33

T₂ = 573.368 K
T₂ = 573.368 - 273 = 300.368 °C

=
=
W = 434.53 kJ/kg