Answer:
The value is 
Explanation:
From the question we are told that
The current is 
The radius is 
The length of the wire is 
\
The resistance is 
The outer surface temperature is 
The average thermal conductivity is 
Generally the heat generated in the stainless steel wire is mathematically represented as
=> 
=> 
Generally the middle temperature is mathematically represented as
Well first of all, when it comes to orbits of the planets around
the sun, there's no such thing as "orbital paths", in the sense
of definite ("quantized") distances that the planets can occupy
but not in between. That's the case with the electrons in an atom,
but a planet's orbit can be any old distance from the sun at all.
If Mercury, or any planet, were somehow moved to an orbit closer
to the sun, then ...
-- its speed in orbit would be greater,
-- the distance around its orbit would be shorter,
-- its orbital period ("year") would be shorter,
-- the temperature everywhere on its surface would be higher,
-- if it has an atmosphere now, then its atmosphere would become
less dense, and might soon disappear entirely,
-- the intensity of x-rays, charged particles, and other forms of
solar radiation arriving at its surface would be greater.
Answer:
Venus is only 95% the size of Earth, and 81% of its mass. With the smaller size and mass, the force of gravity pulling you on the surface is lower. To get your weight on Venus, just multiply your current weight by 0.9. That's why 100 pounds becomes 90 pounds
Answer:
<em>c. The astronaut does not need to worry: the charge will remain on the outside surface.</em>
<em></em>
Explanation:
The astronaut need not worry because <em>according to Gauss's law of electrostatic, a hollow charged surface will have a net zero charge on the inside.</em> This is the case of a Gauss surface, and all the charges stay on the surface of the metal chamber. This same principle explains why passengers are safe from electrostatic charges, in an enclosed aircraft, high up in the atmosphere; all the charges stay on the surface of the aircraft.
Answer:
Explanation:
There is reflection ( two times ) from upper and lower surface of the film . In both cases , reflection is from low to high density medium so there is change in phase of 180 twice .
So for constructive interference
2μd = n λ₁ , d is thickness required , λ is wavelength n₁ is order of bright fringe
For destructive interference ( minimum light )
2μd = (2n+1) λ₂/2
n λ₁ =(2n+1) λ₂/2
(2n+1) / 2n = λ₁ / λ₂
= 650 / 505
= 5 / 4 ( approx )
2n = 4
n = 2
2μd = n λ₁
2 x 1.33 x d = 2 x 650 nm
d = 488.72 nm
