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Luba_88 [7]
4 years ago
6

Are the items in the list renewable or nonrenewable resources?

Physics
2 answers:
Elza [17]4 years ago
8 0
N
R
R
R
N
Hope this helps.
Hitman42 [59]4 years ago
8 0
Nonrenewable- Coal, Silver, soil and diamonds  Renewable- Water 


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The speed of sound in sea water is about 1530 m/s. If a sound wave has a frequency of 2.50 x 10^2 Hz, what is its wavelength in
Setler [38]

Answer: 6.12metres

Explanation:

The wavelength is the distance covered by the wave in one complete cycle. It is measured in metres, and represented by the symbol λ

Recall that Wavespeed (V) = Frequency F x wavelength λ

V = F λ

In this case,

Wavespeed of sound = 1530 m/s

Frequency of sound = 2.50 x 10^2 Hz

Wavelength = ? (let the unknown value be Z)

Apply V = F λ

1530 m/s = 2.50 x 10^2 Hz x Z

Z = (1530 m/s / 2.50 x 10^2 Hz)

Z = (1530 m/s / 250Hz)

Z = 6.12m

Thus, the wavelength of sound in sea water is 6.12m

5 0
4 years ago
a car traveling at a velocity of 2 m/s undergoes an acceleration of 4.5 m/s^2 over a distance of 340 m. How fast will it be goin
ra1l [238]
Vi = 2m/s
a= 4.5 m/s 
d= 340 m
vf= ?

use this equation ...  vf^2=vi<span>^2+2ad

you should get vf = 55.3
hope this helps </span>
3 0
3 years ago
How to measure the weight of an object??? HELP! ​
Luba_88 [7]

Answer:

Weight is a measure of the force of gravity pulling down on an object

mass*force

3 0
3 years ago
A substance maintaining a uniform appearance throughout
777dan777 [17]
Is there anything else you can add for context
5 0
3 years ago
A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/
KatRina [158]

Complete Question

A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/h, 18.0 min at 80.0 km/h, and 60.0 min at 60.0 km/h and spends

25.0 min eating lunch and buying gas

What is the total distance traveled over the entire trip (in km)

Answer:

The value is D = 139.02 \ km

Explanation:

From the question we are told that

For t_1 =  55 min = \frac{55}{60}  =  0.917 \ h the speed is v_1 =  60 \  km/h

For t_2 =  18 min  = \frac{18}{60}  =  0.3 \ h the speed is v_2 =  80 \  km/h

For t_3 = 60 min = \frac{60}{60}  =  1 \ h the speed is v_3 =  60\  km/h

The time taken to have lunch is t _l  = 25 \  min =  \frac{25}{60} =  0.42 \  h

Generally the total distance traveled over the entire trip (in km) is mathematically represented as

D = t_1 *  v_1 + t_2 * v_2 + t_3 * v_3

=>   D = 0.917  *  60 +  0.3 * 80 +  1  * 60

=>   D = 55.02  + 24 +   60

=>   D = 139.02 \ km

4 0
4 years ago
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