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Luba_88 [7]
4 years ago
6

Are the items in the list renewable or nonrenewable resources?

Physics
2 answers:
Elza [17]4 years ago
8 0
N
R
R
R
N
Hope this helps.
Hitman42 [59]4 years ago
8 0
Nonrenewable- Coal, Silver, soil and diamonds  Renewable- Water 


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At a given point in its orbit, the moon is 2.4 x 10^5 miles from earth. How long does it take light from a source on earth to re
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Answer:

Total time= 2.56 s

Explanation:

Given that

Distance = 2.4\times 10^5\ miles

So distance = 386242560 m

Velocity of light

C= 3\times 10^8\ m/s

We know that

Distance = velocity x time

Now by putting then values

time=\frac{386242560}{3\times 10^8}

t=1.28 s

So the total time = 2 x 1.28

total time= 2.56 s

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4 years ago
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I need help please only way to put my grade up !!!!!! Would appreciate it !!! Someone who’s good at this
motikmotik

Answer:

Total energy = 1000J

KE = 500J

PE = 500J

Explanation:

As you may know, the equation for gravitational potential energy is mgh (weight x height)

If the skateboard is halfway down, that means it is at half the height. As the skateboard speeds up (as it goes downward), the potential energy becomes kinetic energy. Since it has 500J of kinetic energy at half way down, it means it had double that amount of Potential energy at the top (1000J). Since half of that became kinetic energy, there is only 500J of PE left.

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KE = 500J

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3 0
3 years ago
When mantle rocks near the radioactive core are heated, they become less dense than the cooler, upper mantle rocks. These warmer
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C.convection cells is the right answer
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3 years ago
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How do I find final velocity
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3 years ago
Water flowing through a cylindrical pipe suddenly comes to a section of pipe where the diameter decreases to 86% of its previous
Orlov [11]

Answer:

Explanation:

The speed of the water in the large section of the pipe is not stated

so i will assume 36m/s

(if its not the said speed, input the figure of your speed and you get it right)

Continuity equation is applicable for ideal, incompressible liquids

Q the flux of water that is  Av with A the cross section area and v the velocity,

so,

A_1V_1=A_2V_2

A_{1}=\frac{\pi}{4}d_{1}^{2} \\\\ A_{2}=\frac{\pi}{4}d_{2}^{2}

the diameter decreases 86% so

d_2 = 0.86d_1

v_{2}=\frac{\frac{\pi}{4}d_{1}^{2}v_{1}}{\frac{\pi}{4}d_{2}^{2}}\\\\=\frac{\cancel{\frac{\pi}{4}d_{1}^{2}}v_{1}}{\cancel{\frac{\pi}{4}}(0.86\cancel{d_{1}})^{2}}\\\\\approx1.35v_{1} \\\\v_{2}\approx(1.35)(38)\\\\\approx48.6\,\frac{m}{s}

Thus, speed in smaller section is 48.6 m/s

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3 years ago
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