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Sonbull [250]
3 years ago
15

Where can carbon be found in the biodome?

Chemistry
2 answers:
Artist 52 [7]3 years ago
4 0
It can be found inside the ground where there are plant roots, remains of animals, and nutrients.
TEA [102]3 years ago
3 0

Answer:

In forests, Most carbon in the terrestrial biosphere is stored in forests: they hold 86% of the planet's terrestrial above-ground carbon and forest soils also hold 73% of the planet's soil carbon. Carbon stored inside plants can be transferred into other organisms during plant consumption.

Hope this helps!

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1, If the “R” under the group title represent the elements in that group, then how any atoms of Na (sodium) will react with 1 at
goblinko [34]

Answer:

NaH one atom of sodium react with one hydrogen to form sodium hydride

Explanation:

5 0
3 years ago
GIVING BRAINLEST TO WHOEVER GETS THE RIGHT ANSWER!! Plz and thx
LenKa [72]

Answer:

Mechanical

Explanation:

5 0
3 years ago
Read 2 more answers
12. Electrons in the first energy level have the least amount of energy.
ludmilkaskok [199]

Answer:

True

Explanation:

Electrons that are in the first energy level (energy level 1) are closest to the nucleus and will have the lowest energy. Electrons further away from the nucleus will have higher energy. An atom's electron shell can accommodate 2n2 electrons, where n is the energy level.

6 0
3 years ago
Of the atoms listed below, which one will have at least one electron in its d orbital?
Oksanka [162]

Answer:

D. Cr

Explanation:

In order to determine which atom has at least one electron in its d orbital, we have to write their theoretical electron configurations.

  • ₁₂Mg 1s² 2s² 2p⁶ 3s²
  • ₁₉K 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹
  • ₁₆S 1s² 2s² 2p⁶ 3s² 3p⁴
  • ₂₄Cr 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁴

Cr has 4 electrons in d orbitals. Cr belongs to the d-block in the periodic table.

5 0
4 years ago
g A chemist combines 59.9 mL of 0.282 M potassium bromide with 15.4 mL of 0.512 M silver nitrate. (a) How many grams of silver b
Rufina [12.5K]

Answer:

m_{AgBr}=1.48gAgBr

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

KBr(aq)+AgNO_3(aq)\rightarrow AgBr(s)+KNO_3(aq)

Thus, since the potassium bromide and silver nitrate are in a 1:1 mole ratio, the first step is to identify the limiting reactant, by considering the reacting volumes of reactants in order to compute the available moles of potassium bromide and the moles of potassium bromide consumed by the 15.4 mL of 0.512-M solution of silver nitrate:

n_{KBr}=0.0599L*0.282\frac{molKBr}{L} =0.0169molKBr\\\\n_{KBr}^{consumed}=0.0154L*0.512\frac{molAgNO_3}{L} *\frac{1molKBr}{1molAgNO_3}=0.00788molKBr

In such a way, since less moles are consumed than available, we infer that silver nitrate is the limiting reactant, for which the resulting grams of silver bromide (molar mass 187.8 g/mol) result:

m_{AgBr}=0.00788molAgNO_3*\frac{1molAgBr}{1molAgNO_3} *\frac{187.8gAgBr}{1molAgBr} \\\\m_{AgBr}=1.48gAgBr

Best regards.

6 0
4 years ago
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