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Iteru [2.4K]
3 years ago
8

Which of the following solutions would have the highest osmotic pressure?

Chemistry
1 answer:
Gennadij [26K]3 years ago
8 0

Answer:

Option d. 0.10 m Cr₂(SO₄)₃

Explanation:

Formula for the osmotic pressure is determined as:

π = M . R . T . i

So you have to take account the i (Van't Hoff factor, numbers of ions dissolved)

  • CH₄N₂O → 0.35 m

Urea is an organic compound, so the i value is 1

  • H₂O → The i is also 1
  • Zn(CH₃COO)₂ → 0.15 m

Zync acetate can be dissociated:

Zn(CH₃COO)₂  →  1Zn²⁺  + 2CH₃COO⁻

In this case, the i is 3. (you see, the stoichiometry of ions)

Cr₂(SO₄)₃ →  0.10 m

Chromium sulfate is dissociated:

Cr₂(SO₄)₃ →  2Cr³⁺  +  3SO₄⁻²

i = 5

BaI₂ → 0.16 m

BaI₂ →  1Ba²⁺  +  2I⁻

i = 3

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false

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Which coefficient before potassium (K) balances this chemical equation?
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Answer:

The coefficient before potassium (K) balances this chemical equation is 2.

Explanation:

_K +Cl₂ → 2KCl

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How is the gravitational force related to the distance between two objects?
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The gravitational force is related to the distance between two objects because it is inversely proportional to the square of the distance.

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4 0
2 years ago
You can practice converting between the mass of a solution and mass of solute when the mass percent concentration of a solution
vfiekz [6]

Answer:

450. g of 0.173 % KCN solution contains 779 mg of KCN.

Explanation:

Mass of the solution = m

Mass of the KCN in solution = 779 mg

Mass by mass percentage of KCN solution = 0.173%

(m/m)\%=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 100

0.173\%=\frac{779 mg}{m}\times 100

m=\frac{779 mg}{0.173}\times 100= 450,289 mg

1 mg = 0.001 g

m = 450,289 mg × 0.001 g = 450.289 mg ≈ 450. g

450. g of 0.173 % KCN solution contains 779 mg of KCN.

6 0
3 years ago
43 milliliters of water weighs 43 g. what is the density of the water?
Anastaziya [24]

Answer:

\rho =1g/mL

Explanation:

Hello,

In this case, since the density is defined as the ratio between the mass and the volume as shown below:

\rho =\frac{m}{V}

We can compute the density of water for the given 43 g that occupy the volume of 43 mL:

\rho =\frac{43g}{43mL}=1g/mL

Regards.

4 0
3 years ago
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