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Vesna [10]
2 years ago
9

It takes 60 mL of 0.20 M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (H2CO3) for the following chemical reac

tion:
2 NaOH + H2CO3 → N2CO3 + 2 NaOH

The concentration of the carbonic acid is _____.
A) 0.48m
B) 0.10m
C) 0.96m
d)0.24m
Chemistry
1 answer:
irina1246 [14]2 years ago
3 0

If It takes 60mL of 0.20M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (H_2CO_3), then the concentration of the carbonic acid is 0.24M

The reaction between NaOH solution and H_2CO_3 is written below

2NaOH + H_2CO_3 \rightarrow Na_2CO_3 + 2H_2O

Volume of NaOH, V_B = 60 ml

Volume of H_2CO_3, V_A=25 ml

Molarity of H_2CO_3, C_A=?

Molarity of NaOH, C_B=0.20M

Number of moles of H_2CO_3, n_A=1

Number of moles of NaOH, n_B=2

The mathematical equation for neutralization reaction is:

\frac{C_AV_A}{C_BV_B} =\frac{n_A}{n_B}

Substitute  C_B=0.2 M,  n_A=1,  n_B=2,  V_B = 60ml, and  V_A=25 ml into the equation above in order to solve for C_A

\frac{C_A \times 25}{0.2 \times 60}=\frac{1}{2}  \\\\50C_A=12\\\\C_B=\frac{12}{50} \\\\C_B=0.24M

Therefore, the concentration of the carbonic acid is 0.24M

Learn more here: brainly.com/question/25943090

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