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Anarel [89]
3 years ago
11

A diver initially moving horizontally with speed v dives dives offthe edge of a vertical cliff and lands in the water a distance

dfrom the base of the cliff. How far from the base of the cliffwould the diver have landed if the diver initially had been movinghorizontally with speed 2v?
A. d
B. √(2d)
C. 2d
D. 4d
E. It cannot be determined unless the hieght of the cliff isknown
Physics
1 answer:
Aliun [14]3 years ago
7 0

Answer:

Option C is correct

Explanation:

"The time is determined by the vertical distance. The formula is sqr(2d/a) = t. There still is no acceleration in the horizontal direction."

For the first drive

d = d

t = sqr(2d/a)

r = v  

For the Second drive

d = ??

t = sqr(2d/a)

r = 2v

Since the times are same, equate the results.

t = d/v = d1/2v

v*d1 = 2v*d The v's cancel because they are related.

d1 = 2d.

You go twice as far as you did before.

Option C is correct

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The relation between the potential difference and the electric field between the plates of the parallel plate capacitor is given by :

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Differentiating on both the sides with respect to time, we get

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Therefore, the rate of the electric field changes between the plates of the parallel plate capacitor is given by :

$\frac{dE}{dt}=\frac{1}{D}\frac{dV}{dt}$

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6 0
3 years ago
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Soloha48 [4]

The momentum of the second ball was 15 kg.m/s.

<h3>What is inelastic collision?</h3>

In which collision some amount of kinetic energy of the system is lost that called inelastic collision. In purely inelastic collision, two bodies stick together. But principle of conservation of linear momentum is obeyed.

In the given question,

Two balls collide and after collision, the final momentum of the system = 18 kg.m/s.

Initial velocity of 1st ball of mass 3 kg is 1 m/s.

So, Initial momentum of first ball = mass × velocity = (3 kg) × (1 m/s) = 3 kg.m/s.

According to Principle of conservation of linear momentum for this inelastic collision,

Initial momentum of first ball + initial momentum of second ball =  final momentum of the system

⇒   initial momentum of second ball =   final momentum of the system - Initial momentum of first ball

= 18 kg.m/s - 3 kg.m/s.

= 15 kg.m/s.

Hence, initial momentum of second ball = 15 kg.m/s.

Learn more about momentum here:

brainly.com/question/24030570

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