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Anarel [89]
3 years ago
11

A diver initially moving horizontally with speed v dives dives offthe edge of a vertical cliff and lands in the water a distance

dfrom the base of the cliff. How far from the base of the cliffwould the diver have landed if the diver initially had been movinghorizontally with speed 2v?
A. d
B. √(2d)
C. 2d
D. 4d
E. It cannot be determined unless the hieght of the cliff isknown
Physics
1 answer:
Aliun [14]3 years ago
7 0

Answer:

Option C is correct

Explanation:

"The time is determined by the vertical distance. The formula is sqr(2d/a) = t. There still is no acceleration in the horizontal direction."

For the first drive

d = d

t = sqr(2d/a)

r = v  

For the Second drive

d = ??

t = sqr(2d/a)

r = 2v

Since the times are same, equate the results.

t = d/v = d1/2v

v*d1 = 2v*d The v's cancel because they are related.

d1 = 2d.

You go twice as far as you did before.

Option C is correct

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How are balanced and unbalanced forces related to motion?
Aliun [14]

Answer:

Balanced forces do not result in any change in motion. forces: forces applied to an object in opposite directions that are not equal in size. Unbalanced forces result in a change in motion.

Explanation:

4 0
3 years ago
Read 2 more answers
An electron passes through a point 2.83 cm 2.83 cm from a long straight wire as it moves at 35.5 % 35.5% of the speed of light p
igor_vitrenko [27]

Answer:

The magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

Explanation:

Given:

Distance from the wire to the field point r = 2.83 \times 10^{-2} m

Speed of electron v = 35.5 \%c

Current I = 17.7 A

For finding the acceleration,

First find the magnetic field due to wire,

  B = \frac{\mu _{o}I }{2\pi r }

Where \mu_{o} = 4\pi   \times 10^{-7}

  B = \frac{4\pi \times 10^{-7}  \times 17.7 }{2\pi (2.83 \times 10^{-2} ) }

  B = 12.50 \times 10^{-5} T

The magnetic force exerted on the electron passing through straight wire,

  F = qvB  

  F = 1.6 \times 10^{-19} \times 0.355 \times 3 \times 10^{8} \times 12.50 \times 10^{-5}

  F = 21.3 \times 10^{-16} N

From the newton's second law

  F = ma

Where m = mass of electron = 9.1 \times 10^{-31} kg

So acceleration is given by,

   a = \frac{F}{m}

   a = \frac{21.3 \times 10^{-16} }{9.1 \times 10^{-31} }

   a = 2.34 \times 10^{15} \frac{m}{s^{2} }

Therefore, the magnitude of electron acceleration is 2.34 \times 10^{15} \frac{m}{s^{2} }

7 0
3 years ago
The majority of the elements on the periodic table are _______. A. gases B. nonmetals C. metals D. liquids
Paladinen [302]

Option (C) is correct that the majority of the elements on the periodic table are metals.

#$# THANK YOU #$#

7 0
3 years ago
You run 100 meters in 50 seconds. Calculate your speed, label with m/s
NemiM [27]

Answer:

2 m/s

Explanation:

speed = distance/time

s = 100/50 = 2

4 0
3 years ago
1. What is the acceleration of a car that goes from 20 Km/hr to 100 km/hr in 8 seconds?
san4es73 [151]

Answer:

10 :)

You have to divide the difference of speed and divide it by the time. So 100-20 would be 80, and if you divide that by 8 it would be 10.

Hope this helps.

7 0
3 years ago
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