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Oksanka [162]
3 years ago
8

In Rutherford's gold foil experiment, most alpha particles passed through the gold foil without deflection and were detected on

the screen. What caused the particles to pass through without any deflection? A. a large area of positively charged particles present in the gold foil. B. the extremely high speed of the alpha particles passing through the gold foil. C. a small area of negatively charged particles present in the gold foil. D. empty space in the atoms present in the gold foil.
Chemistry
1 answer:
Gwar [14]3 years ago
7 0

Answer:

Option D.

Explanation:

Some of the alpha particles Rutherford shot at the gold foil bounced back, some scattered; but the majority of them went right through. That meant there had to be some sort of positively charged subatomic particle in there that pulled them through, but it had to be at the center and couldn't take up a lot of room.

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A sample of gas initially occupies 4.25 L at a pressure of 0.850 atm at 23.0°C. What will the volume be if the temperature is ch
Akimi4 [234]

Answer:

2.31\text{ L}

Explanation:

Here, we want to calculate the final volume

We use the general gas equation here:

\frac{P_1V_1}{T_1}\text{ = }\frac{P_2V_2}{T_2}

P1 is the initial pressure which is 0.850 atm

V1 is the initial volume which is 4.25 L

T1 is the initial temperature which is (23 + 273.15 = 296.15 K)

P2 is the final pressure which is 1.50 atm

V2 is the final volume which is unknown

T2 is the final temperature (11.5 + 273.15 = 284.65 K)

Substituting the values, we have:

\begin{gathered} \frac{0.850\text{ }\times4.25}{296.15}\text{ = }\frac{1.50\times V_2}{284.65} \\  \\ V_2\text{ = }\frac{284.65\text{ }\times0.850\times4.25}{1.5\times296.15} \\  \\ V_2\text{ = 2.31 L} \end{gathered}

6 0
1 year ago
73.5 mol of P4O10 contains how many moles of P ? moles of P:
Sholpan [36]

Answer:

294 moles of P

Explanation:

For every 1 mol of P4O10 contains 4 mol of P

so;

73.5 mol P4O10 × <u> </u><u> </u><u> </u><u> </u><u> </u><u>4 mol P</u><u> </u><u> </u><u> </u><u> </u><u> </u>

1 mol P4O10

= 73.5 × 4

= 294 moles of P

7 0
2 years ago
A substance has a high melting point and conducts electricity in the liquid phase The is substance is
posledela

Answer:

oxygen

Explanation:

?

3 0
3 years ago
If enough changes occur in the gene pool of a species, it is possible that a new species would be created.
lianna [129]

Answer:

Yes

Explanation:

A gene pool is the sum total of all the genes(sum of alleles)of a species and population at any given time is known as gene pool.

The new species are created in nature by four mechanisms such as geographic isolation (allopatric speciation), reproductive isolation (sympatric speciation), mating behaviour (parapatric speciation).

Due to any of these factors when population acquire unique changes in their genes and enough changes have been introduced in the gene pool of the population with time, two population become distinct from each other and not able to interbreed leads to the formation of new species.

6 0
3 years ago
How many grams of water are needed to dissolve 27.8 g of ammonium nitrate NH4NO3 in order to prepare a 0.452 m solution?
Vanyuwa [196]

Answer: 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

Explanation:

Molality : It is defined as the number of moles of solute present per kg of solvent

Formula used :

Molality=\frac{n\times 1000}{W_s}

where,

n= moles of solute

Moles of NH_4NO_3=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{27.8g}{80.0g/mol}=0.348moles  

W_s = weight of the solvent in g = ?

0.452=\frac{0.348\times 1000}{W_s}

W_s=770g

Thus 770 g water are needed to dissolve 27.8 g of ammonium nitrate NH_4NO_3 in order to prepare a 0.452 m solution

5 0
3 years ago
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