Given:
450 grams of water (Tw = 24 C)
Thermal capacity of the beaker = negligible
Q = 0
Tice = 0 C
Tfinal = 8 C
450g * (Tf - Tw) + m_ice * (Tice - Tw) = 0
450g * (8 - 24) + m_ice (0 - 24) = 0
solve for m_ice
There's no general rule.
Displacement is the length of a straight line from start to finish, and distance is how far you actually traveled from start to finish.
The only thing we really know is that distance can never be shorter than displacement. So I guess the answer is:
<em>The numerical ratio of displacement to distance is always 1 or less</em>.
(But it has to be written ALL IN CAPITALS.)
Answer:
The current at time t = 4.00 s is 0.766 A.
Explanation:
Given that,
The quantity of charge through a conductor is modeled as :

We need to find the current (in A) at time t = 4.00 s. We know that the rate of change of electric charge is called electric current. It is given by :

At t = 4 s

So, the current at time t = 4.00 s is 0.766 A. Hence, this is the required solution.
If you increase the voltage you increase the current