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11Alexandr11 [23.1K]
3 years ago
9

Walter was heating some cubes of ice while conducting an experiment. At one point, the ice melted into water. What is the correc

t term used to describe the amount of heat required to prompt a phase change?
A.
boiling point
B.
melting point
C.
heat of fusion
D.
heat of vaporization
E.
freezing point
Chemistry
2 answers:
bonufazy [111]3 years ago
8 0
I think B I could be wrong
marusya05 [52]3 years ago
7 0

Answer: Option (C) is the correct answer.

Explanation:

When one mole of a substance is heated to change its phase from solid to liquid then the heat required to bring this change is known as heat of fusion.

Whereas a point where vapor pressure of liquid equals the atmospheric pressure of the surrounding liquid then it is known as boiling point.

A temperature where a substance starts to melt is known as melting point.

Heat of vaporization is defined as the amount of heat required to change one mole of a liquid into vapor state.

Whereas a point of temperature where liquid turns into solid is known as freezing point.

Thus, we can conclude that the correct term used to describe the amount of heat required to prompt a phase change in the given situation is heat of fusion.

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<span>An example of sublimation is when a dry ice changes to carbon dioxide when kept in an open container. Sublimation is a change from solid phase to gas phase without passing through the liquid state. In this example, it is clear that the dry ice is solid form and it evaporates as gas without passing through the liquid state.</span>
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Which of the following would make a solution?
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Answer:

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A generic weak acid with formula HA has a Ka = 2.76 x 10-8. Calculate the Kb for the conjugate base of the acid.
Reika [66]

Answer:

3.62x10⁻⁷ = Kb

Explanation:

The acid equilibrium of a weak acid, HX, is:

HX + H₂O ⇄ X⁻ + H₃O⁺

Where Ka = [X⁻] [H₃O⁺] / [HX]

And basic equilibrium of the conjugate base, is:

X⁻ + H₂O ⇄ OH⁻ + HX

Where Kb = [OH⁻] [HX] / [X⁻]

To convert Ka to Kb we must use water equilibrium:

2H₂O ⇄ H₃O⁺ + OH⁻

Where Kw = 1x10⁻¹⁴ = [OH⁻] [H₃O⁺]

Thus, we can obtain:

Kw = Ka*Kb

Solving for Kb:

Kw / Ka = Kb

1x10⁻¹⁴ /  2.76x10⁻⁸ =

3.62x10⁻⁷ = Kb

4 0
3 years ago
The isotope \left.\begin{array}{r}212 \\ 83\end{array}\right? Bi has a half-life of 1.01 yr. What mass (in mg) of a 2.00-mg samp
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Half-life is the length of time it takes for half of the radioactive atoms of a specific radionuclide to decay. A good rule of thumb is that, after seven half-lives, you will have less than one percent of the original amount of radiation.

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half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay (change spontaneously into other nuclear species by emitting particles and energy), or, equivalently, the time interval required for the number of disintegrations per second of a radioactive.

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Since the chemical bonding between atoms involves the deformation of atomic electron wavefunctions, the radioactive half-life of an atom can depend on how it is bonded to other atoms. Simply by changing the neighboring atoms that are bonded to a radioactive isotope, we can change its half-life.

Learn more about half life of an isotope here:

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5 0
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HELP! I WILL GIVE BRAINLIST!
Dominik [7]

Answer:

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Explanation:

i hope this helps

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