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Sidana [21]
2 years ago
5

I need help plz..

Chemistry
2 answers:
KiRa [710]2 years ago
6 0

Answer:

1. protoplasm

2. the study of geckos!

Explanation:

I just know these facts :D

Anuta_ua [19.1K]2 years ago
4 0

Answer:

1. a simulation 2. saurology

Explanation:

You might be interested in
How many grams of aluminum oxide (Al2O3) will be formed from 10.0 grams of aluminum (Al)? 4 AL + 3 02 --> 2 AL203​
d1i1m1o1n [39]

Answer:

Mass = 18.9 g

Explanation:

Given data:

Mass of Al₂O₃ formed = ?

Mass of Al = 10.0 g

Solution:

Chemical equation:

4Al + 3O₂      →       2Al₂O₃

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 10.0 g/ 27 g/mol

Number of moles = 0.37 mol

Now we will compare the moles of Al and Al₂O₃.

                      Al          :          Al₂O₃

                       4           :            2

                     0.37        :         2/4×0.37 = 0.185 mol

Mass of Al₂O₃:

Mass = number of moles × molar mass

Mass = 0.185 mol × 101.9 g/mol

Mass = 18.9 g

4 0
3 years ago
PLEASE HELP
torisob [31]

Decrease

Increase  

Increase

Decrease

Increase

Decrease

Hope this helps! :)

4 0
3 years ago
Draw the major organic substitution product(s) for (2R,3S)-2-bromo-3-methylpentane reacting with the given nucleophile. Indicate
Ede4ka [16]

Answer:

The final product of the reaction is (<em>2S,3S</em>)-2-ethoxy-3-methylpentane.

Explanation:

The given reaction undergoes S_{N}2  mechanism in which the nucleophile attacks the backside and it is substituted by the elimination of bromine.

Due to the backside attack of nucleophile , the inverse in stereo-chemistry is observed.

After the substitution of ethoxy group, the configuration is assigned according to the priority it shows clock wise direction(R) - configuration.

When hydrogen faces the front side , it results shows inverse configuration i.e, S- configuration.

The chemical reaction is as follows.

 

6 0
3 years ago
How many molecules of CaCi2 are equivalent to 75.9 grams
horsena [70]
<em>M CaCl₂: 40+(35,5×2) = 111 g/mol</em>


6,02·10²³ molecules ---------- 111g
X molecules --------------------- 75,9g
X = (75,9×<span>6,02·10²³)/111
X = <u>4,116</u></span><span><u>·10²³</u> molecules of CaCl</span>₂

:)
8 0
3 years ago
someone pls help me with my chemistry test plsss my teacher changes the questions so I can't search them up. its 21 questions so
shusha [124]

Answer:

Correct option is

B

5 liters of CH

4

(g)NO

2

at STP

No. of molecules=

22.4

5

mol=

22.4

5

×N

A

molecules

A) 5ℊ of H

2

(g)

No. of moles=

2

5

mol=

2

5

×N

A

molecules

B) 5l of CH

4

(g)

No. of moles of CH

4

=

22.4

5

mol=

22.4

5

N

A

molecules

C) 5 mol of O

2

=5N

A

O

2

molecules

D) 5×10

23

molecules of CO

2

(g)

Molecules of 5l NO

2

(g) at STP=5l of CH

4

(g) molecules at STP

Therefore, option B is correct.

7 0
3 years ago
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