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2 years ago

I need help plz..

Chemistry

2 answers:

KiRa [710]2 years ago

6 0

Answer:

1. protoplasm

2. the study of geckos!

Explanation:

I just know these facts :D

Anuta_ua [19.1K]2 years ago

4 0

Answer:

1. a simulation 2. saurology

Explanation:

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All of the following are diatomic molecules except? a)H b)Br c) CI d)S

xxTIMURxx [149]

d)S is not one of them.

Here's an easy way to remember them, attached:

8 0

3 years ago

Read 2 more answers

10. Which of the following best describes the reaction 2VO3– (aq) + Zn (s) + 8H+ (aq) → 2VO2 (aq) + Zn2+ (aq) + 4H2O (l)? ______

Oduvanchick [21]

Correct answer is option E. It is a redox reaction in which Zn is oxidized at the anode, and V is reduced at the cathode.

Reason:
In above reaction, the oxidation state of VO3- is +5, while that of VO2 is +4. Thus there is reduction of V from +5 to +4
In case of Zn, oxidation state of Zn is increased from 0 to +2, Thus process is referred as oxidation.

3 0

3 years ago

Describe the structure of atoms including the masses, electrical, charges, and locations of protons, neutrons in the nucleus ,an

steposvetlana [31]

Answer:

The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge).

Explanation:

The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge).

3 0

3 years ago

You want to slow down the following reaction:

zimovet [89]

Iron oxide is rust. So oil would be an inhibitor.

4 0

3 years ago

A 40.0-L sample of fluorine is heated from 90.0°C to 186.0°C. What volume will the sample occupy at the higher temperature?

jasenka [17]

Answer:

The volume will be 82.67 L

Explanation:

Charles's Law is the relationship between the volume and temperature of a certain amount of ideal gas. In this way, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

$\frac{V}{T} = k$

Having a certain volume of gas V1 that is at a temperature T1 at the beginning of the experiment, by varying the volume of gas to a new value V2, then the temperature will change to T2, and it will be true:

$\frac{V1}{T1} =\frac{V2}{T2}$

In this case, you know:

V1= 40 L
T1= 90 °C
V2= ?
T2= 186 °C

Replacing:

$\frac{40L}{90C} =\frac{V2}{186 C}$

Solving:

$V2=\frac{40L}{90C} *186 C$

V2= 82.67 L

The volume will be 82.67 L

5 0

3 years ago