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3 years ago

4. Unlike a gas, plasma can

Physics

2 answers:

kap26 [50]3 years ago

4 0

Answer:

Unlike a gas, plasma can conduct electricity and respond to magnetism. That's because plasma contains charged particles called ions.

fenix001 [56]3 years ago

3 0

Answer:

a) The pressure in a traveling sound wave is given by the equation

p Pa π m x s t − − Δ = −

s x, t 6.0 nm cos kx+ 3000 rad / s t+ ( )( ) ( ) ( )

Find the (a) pressure amplitude, (b) frequency, (c) wavelength,

and (d) speed of the wave.

b) If the form of a sound wave traveling through air is

= ϕ , how much time does any given air molecule along

the path take to move between displacements s = + 2.0 nm and s = - 2.0 nm?

Solution: (a) The amplitude of a sinusoidal wave is the numerical coefficient of the sine (or

cosine) function: pm = 1.50 Pa.

We identify k = 0.9π and ω = 315 π (in SI units), which leads to f = ω /2 π = 158 Hz.

We also obtain λ = 2π/k = 2.22 m.

The speed of the wave is v = λ /k = 350 m/s.

(b) Without loss of generality we take x = 0, and let t = 0 be when s = 0. This means the

phase is φ= -π/2 and the function is s = (6.0 nm)sin(ωt) at x = 0. Noting that ω = 3000 rad/s,

we note that at t = sin-1(1/3)/ω = 0.1133 ms the displacement is s = +2.0 nm. Doubling that

time (so that we consider the excursion from –2.0 nm to +2.0 nm) we conclude that the time

required is 2(0.1133 ms) = 0.23 ms.

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An object moves on a trajectory given by Bold r left parenthesis t right parenthesis equals left angle 10 cosine 6 t comma 10 si

spayn [35]

Answer:

Explanation:

(r) = <10 cos 6t, 10 Sin 6t>

The distance traveled by the object is the magnitude of vector r.

The magnitude of vector r is given by

$r = \sqrt{(10 Cos 6t)^{2}+(10 Sin 6t)^{2}}$

$r =10 \sqrt{(Cos^{2} 6t)+(Sin^{2} 6t)$

r = 10

5 0

2 years ago

Two vectors are given by a = 8.6i + 5.1 j and b = 931 + 9.5.

skelet666 [1.2K]

Answer:

Assuming b = 9.3i + 9.5j (b = 931 + 9.5 is wrong):

a) a×b = 34.27k

b) a·b = 128.43

c) (a + b)·b = 305.17

d) The component of a along the direction of b = 9.66

Explanation:

Assuming b = 9.3i + 9.5j (b = 931 + 9.5 is wrong) we can proceed as follows:

a) The vectorial product, a×b is:

$a \times b = (8.6*9.5 - 5.1*9.3)k = 34.27k$

b) The escalar product a·b is:

$a\cdot b = (8.6*9.3) + (5.1*9.5) = 128.43$

c) Asumming (a + b)·b instead a+b·b we have:

$(a + b)\cdot b = [(8.6 + 9.3)i + (5.1 + 9.5)j]\cdot (9.3i + 9.5j) = (17.9i + 14.6j)\cdot (9.3i + 9.5j) = 305.17$

d) The component of a along the direction of b is:

$a*cos(\theta) = \frac{a\cdot b}{|b|} = \frac{128.43}{\sqrt{9.3^{2} + 9.5^{2}}} = 9.66$

I hope it helps you!

5 0

3 years ago

Most reactive non-metals in order?

kompoz [17]

Nonmetals often share or gain electrons. The nonmetals in the periodic table increases as you move to the right and decreases as you go down. This is because, the smaller the atom, the reactive it gets due to less electron attached to the orbits of the atom. The reactivity of nonmetals is arranged in decreasing order. 
Carbon
 Nitrogen
Oxygen
Fluorine
Phosphorus 
Sulfur
Chlorine 
Selenium 
Bromine 
Iodine

5 0

3 years ago

In our Solar System, the inner planets are rocky because Choose one: A. warm temperatures in the inner disk caused the inner pla

xeze [42]

The inner planets are rocky because The warm temperatures in the inner disk caused the inner planetesimals to be formed of mostly rocky material.

What are rocky planets?

Rocky planets are the planet in which constituents are mostly silicate rocks or metal. They are also regarded as a planet with a solid surface.
The formation of rocky planets is said to have occurred billions of years ago and its process of formation is termed accretion. Through accretion are its constituents formed as the more it goes bigger, the higher the rising temperature and pressure in its core and the elements which have to undergo accreted heat up, melt, and spread. Through this process, heavier elements go deeper into the core of the planet and lighter elements float toward the surface.
In the formation of rocky planets, the inner portions of the disk are said to be warm from the protostar thereby resulting in the production of the heavy elements that stay there.