Answer:
The concentration of acetic acid present in the vinegar is 0.113M
Explanation:
1. As the titration occurs between an acid and a base is called neutralization. The balanced chemical reaction between the acetic acid and the NaOH is:
2. Calculate the moles of NaOH used, taking in account the concentration of NaOH 1.00M:
3. Calculate the number of moles of acetic acid neutralized using stoichiometry:
4. Calculate the concentration of acetic acid present in the vinegar:
Responder:
18.75 atmósferas
Explicación:
Paso uno:
datos dados
volumen inicial V1 = 25L
Presión inicial P1 = 7.5 atm
volumen final V2 = 10L
presión final P2 = ??
Segundo paso:
Aplicando la expresión de gas que relaciona el volumen y la presión, es decir
P1V1 = P2V2
sustituyendo nuestros datos tenemos
7.5 * 25 = P2 * 10
187.5 = P2 * 10
divide ambos lados por 10
P2 = 187.5 / 10
P2 = 18.75 atmósferas
<em><u>La presión final es de 18.75 atm.</u></em>
Answer:the force is needed to stretch it farther.
Explanation: the definition of force is push or pull so imagine stretching a rubber band your pulling the band which means you increase the force.
Answer:
Option B. 3.0×10¯¹¹ F.
Explanation:
The following data were obtained from the question:
Potential difference (V) = 100 V.
Charge (Q) = 3.0×10¯⁹ C.
Capacitance (C) =..?
The capacitance, C of a capacitor is simply defined as the ratio of charge, Q on either plates to the potential difference, V between them. Mathematically, it is expressed as:
Capacitance (C) = Charge (Q) / Potential difference (V)
C = Q/V
With the above formula, we can obtain the capacitance of the parallel plate capacitor as follow:
Potential difference (V) = 100 V.
Charge (Q) = 3.0×10¯⁹ C.
Capacitance (C) =..?
C = Q/V
C = 3.0×10¯⁹ / 100
C = 3.0×10¯¹¹ F.
Therefore, the capacitance of the parallel plate capacitor is 3.0×10¯¹¹ F.
Answer:
The charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg
Explanation:
From the formulae
F = qvB and F = mv²/r
Where F is Force
q is charge
v is speed
B is magnetic field strength
m is mass
and r is radius
Then,
qvB = mv²/r
qB = mv/r
We can write that
q/m = v/rB ---- (1)
Also
From Electric force formula
F = Eq
Where E is the electric field
and magnetic force formula
F = Bqv
Since, electric force = magnetic force
Then, Eq = Bqv
E = Bv
∴ v = E/B
Substitute v = E/B into equation (1)
q/m = (E/B)/rB
∴ q/m = E/rB²
(NOTE: q/m is the charge to mass ratio)
From the question,
E = 3.10 ×10³ N/C
r = 4.20 cm = 0.0420 m
B = 0.360 T
Hence,
q/m = 3.10 ×10³ / 0.0420 × (0.360)²
q/m = 569517.9306 C/kg
q/m = 5.7 × 10⁵ C/kg
Hence, the charge-to-mass ratio of the particle is 5.7 × 10⁵ C/kg.
