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yKpoI14uk [10]
3 years ago
5

What sound frequency could a human detect?

Physics
2 answers:
ziro4ka [17]3 years ago
8 0

A healthy young person hears all sound frequencies from 20  to 20,000 hertz. I think it also includes 15-18,000 waves, or cycles, per second.


Hope I helped :)

pantera1 [17]3 years ago
6 0

Explanation :

The number of oscillations per unit time is called a frequency of the wave. Its SI unit is Hertz or Hz. It is equivalent to per second.

The hearing range of human ear is 20 Hz - 20,000 Hz. The sound frequency range varies for different animals.

For example, the hearing range of dolphins or bats is up to 1,00,000 Hz. Another example is elephants whose hearing range is 14 Hz to 16 Hz.

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Cesium-137 undergoes beta decay and has a half-life of 30.0 years. How many beta particles are emitted by a 14.0-g sample of ces
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Answer: 0.81\times 10^{16} beta particles

Explanation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

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\text{Number of moles of cesium}=\frac{14.0g}{137g/mol}=0.102moles

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of cesium contains atoms =  6.023\times 10^{23}

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The relation of atoms with time for radioactivbe decay is:

N_t=N_0\times \frac{1}{2}^{\frac{t}{t_{\frac{1}{2}}}}

Where N_t =atoms left undecayed

N_0 = initial atoms

t = time taken for decay = 3 minutes

{t_{\frac{1}{2}}} = half life = 30.0 years = 1.577\times 10^7 minutes

The fraction that decays  :  1-(\frac{1}{2})^{\frac{3}{1.577\times 10^7}}=1.32\times 10^{-7}

Amount of particles that decay is  = 0.614\times 10^{23}\times 1.32\times 10^{-7}=0.81\times 10^{16}

Thus 0.81\times 10^{16} beta particles are emitted by a 14.0-g sample of cesium-137 in three minutes.

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