Solubility Curve Practice Problems Worksheet 1
1 answer:
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To solve this problem we will use the definition of the period in a simple pendulum, which warns that it is dependent on its length and gravity as follows:
Here,
L = Length
g = Acceleration due to gravity
We can realize that is a constant so it is proportional to the square root of its length over its gravity,
Since the body is in constant free fall, that is, a point where gravity tends to be zero:
The value of the period will tend to infinity. This indicates that the pendulum will no longer oscillate because both the pendulum and the point to which it is attached are in free fall.
The direction of the force changes, so, the ion will now rotate in the opposite direction
Explanation:
The force experienced by a moving charge in a magnetic field is (assuming the motion of the charge is perpendicular to the magnetic field)
(1)
where
q is the charge
v is the velocity of the particle
B is the strength of the magnetic field
Moreover, the direction of the force is perpendicular to the motion of the particle: this means that the particle moves in a circular motion under the action of this magnetic force.
Equating this force to the centripetal force,
Where m is the mass of the particle. So we find that the radius of the orbit (r) is
(2)
In this problem, an ion with initial charge +1 picks 2 electrons and its charge becomes -1.
- From eq.(1), we notice that since the sign of q changes, the direction of the force changes as well: so, the ion will now rotate in the opposite direction
- Moreover, from eq.(2) we notice that as the absolute value of q does not change, then the radius of the orbit does not change.