Answer:
Au3+(aq) + 3Cu+(aq) → Au(s) + 3Cu2+(aq)
1.35 V
Explanation:
Given that the reduction potential of
Cu^2+(aq) + e- -----> Cu^+(aq) is +0.15 V
While the reduction potential of
Au3+(aq) + 3 e- -----> Au(s) is + 1.50V
It is clear that the Cu^+(aq)/Cu^2+(aq) system is the anode while Au^3+(aq)/Au(s) system is the cathode based on the reduction potentials shown above. The number of electrons transferred (n) =3
E°cell = E°cathode - E°anode
E°cell= 1.50-0.15
E°cell= 1.35 V
In the Bohr's Model of the atom, the protons are located in the nucleus. The electrons move around the nucleus. I hope this helps in some way. (:
Answer:
Group B
Explanation:
The control group of an experiment is considered to be the "normal" because it does not receive the expeiemental treatment and hence is used to compare with the experimental group. The control and experimental groups are similar in every other aspect with the exception of the "INDEPENDENT VARIABLE". The independent variable is not changed in the control group.
In this experiment, the control group is GROUP B, which was given a plain gatorade without adding sugar. Sugar is the independent variable here, and it was not included in GROUP B, meaning that GROUP B is the CONTROL GROUP. On the other hand, the experimental group is the GROUP A.
Answer:
i answered your other post with it
Explanation:
