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Aneli [31]
3 years ago
14

An object with a kinetic energy of 2160J has a mass of 120kg. What is the velocity

Physics
1 answer:
luda_lava [24]3 years ago
5 0
Hmmm the only formula i know is v = d * t  or volocity = distance * time
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AP physics Will give brainliest to correct answer.
rjkz [21]

Answer:

the 4th one

Explanation:

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3 years ago
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Mechanical energy is the sum of<br> energy and potential energy.
MAVERICK [17]

Answer:

True, the total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy. This sum is simply referred to as the total mechanical energy.

Explanation: Hope it helps you:))))

have a good day

7 0
2 years ago
URGENT!!
irinina [24]

Answer:

Explanation:La ecuación de Van der Waals es una ecuación de estado de un fluido compuesto de partículas con un tamaño no despreciable y con fuerzas intermoleculares, como las fuerzas de Van der Waals. La ecuación, cuyo origen se remonta a 1873, debe su nombre a Johannes van der Waals, quien recibió el premio Nobel en 1910 por su trabajo en la ecuación de estado para gases y líquidos, la cual está basada en una modificación de la ley de los gases ideales para que se aproxime de manera más precisa al comportamiento de los gases reales al tener en cuenta su tamaño no nulo y la atracción entre sus partículas.

3 0
3 years ago
A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor i
svet-max [94.6K]

Answer:

0.261\ \text{m}

Explanation:

\Delta f = Change in frequency = 2.1 Hz

f = Frequency of source of sound = 440 Hz

v_m= Maximum of the microphone

v = Speed of sound = 343 m/s

T = Time period = 2 s

We have the relation

\Delta f=2f\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f}\\\Rightarrow v_m=\dfrac{2.1\times 343}{2\times 440}\\\Rightarrow v_m=0.8185\ \text{m/s}

Amplitude is given by

A=\dfrac{v_m T}{2\pi}\\\Rightarrow A=\dfrac{0.8185\times 2}{2\pi}\\\Rightarrow A=0.261\ \text{m}

The amplitude of the simple harmonic motion is 0.261\ \text{m}.

4 0
3 years ago
For a long ideal solenoid having a circular cross-section, the magnetic field strength within the solenoid is given by the equat
andrezito [222]

Answer:

Radius of the solenoid is 0.93 meters.

Explanation:

It is given that,

The magnetic field strength within the solenoid is given by the equation,

B(t)=5t\ T, t is time in seconds

\dfrac{dB}{dt}=5\ T

The induced electric field outside the solenoid is 1.1 V/m at a distance of 2.0 m from the axis of the solenoid, x = 2 m

The electric field due to changing magnetic field is given by :

E(2\pi x)=\dfrac{d\phi}{dt}

x is the distance from the axis of the solenoid

E(2\pi x)=\pi r^2\dfrac{dB}{dt}, r is the radius of the solenoid

r^2=\dfrac{2xE}{(dE/dt)}

r^2=\dfrac{2\times 2\times 1.1}{(5)}

r = 0.93 meters

So, the radius of the solenoid is 0.93 meters. Hence, this is the required solution.

4 0
3 years ago
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