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Wewaii [24]
3 years ago
12

Suppose the beam is carrying a known shear load of RD = 28 kN . In this particular situation, the resistance factor is ϕ=0.9 for

the shear load, and the nominal shear stress is 204 MPa . What is the magnitude of the maximum live load (in addition to RD) that can be supported in shear by this beam? Express your answer to three significant figures with the appropriate units.
Engineering
1 answer:
andreyandreev [35.5K]3 years ago
4 0

Answer:

49.5 kN

Explanation:

From the information given:

R_D = 28 \ kN  \delta _D = 1.4;  \ \ \ \delta _L = 1.6

\sigma_n = 204 \ MPa;    \ \ \ A_w = 6.45  \ cm^2 = 645 \ mm^2

Thus ; P_n = \dfrac{\sigma_n}{\frac{1}{A}} \\ \\   = \ {\sigma_n}*{A}  \\ \\ = 645 *204  \\ \\ = 131.58 \ kN

From the given inequality;  maximum live load (in addition to RD) that can be supported in shear by this beam is calculated by using the relation;

\phi P_n \geq \sum \delta_i R_i \\ \\ \geq \delta_DR_D + \delta_L R_L \\ \\ 0.9*131.58 \geqq [1.4*28+1.6*R_L ] \\ \\ 118.4 \geq 39.2+ 16 R_L \\ \\ 118.4 - 39.2 \geq 16R_L  \\  \\ 79.2  \geq 16R_L\\  \\ R_L \leq 49.5 \  kN

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Explanation:

A turbine is a steady-state devices which transforms fluid energy into mechanical energy and is modelled after the Principle of Mass Conservation and First Law of Thermodynamics, whose expressions are described hereafter:

Mass Balance

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Energy Balance

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\dot m = \frac{v_{out}\cdot A_{out}}{\nu_{out}}

v_{out} = \frac{\dot m \cdot \nu_{out}}{A_{out}}

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v_{out} = 680.590\,\frac{m}{s}

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\dot W_{out} = \dot m \cdot (-q_{loss} + h_{in}-h_{out})

\dot W_{out} = \left(16.168\,\frac{kg}{s} \right)\cdot \left(-20\,\frac{kJ}{kg} + 3650.6\,\frac{kJ}{kg} - 2500.2\,\frac{kJ}{kg}\right)

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Step1

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Percentage ductility is calculated as follows:

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