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Anni [7]
3 years ago
12

Potassium has three naturally occurring isotopes. According to one source of data, Potassium-39 (mass 38.9637 amu) makes up 93.2

6%, potassium-40 (mass 39.9640 amu) makes up just 0.01%, and potassium-41 (mass 40.9618 amu) makes up 6.73%. What is the average atomic mass of potassium based on these relative abundances
Chemistry
1 answer:
Nonamiya [84]3 years ago
5 0

Answer:

Average atomic mass of potassium based on these relative abundances

= 39.0944

Explanation:

The atomic mass of this element will be equal to the sum of product of its three isotopic masses and its fractional abundance

For isotope I -

Mass of Potassium-39 =  38.9637 amu

Fractional abundance of Potassium-39 = 93.26 %

Mass of Potassium-40 = 39.9640 amu

Fractional abundance of Potassium-40 = 0.01 %

Mass of Potassium-41 = 40.9618 amu

Fractional abundance of Potassium-41 =  6.73%

Average atomic mass of potassium based on these relative abundances

= (38.9636 * 0.9326)+ (39.9640*0.0001) + (40.9618 * 0.0673)\\= 36.3374 + 0.0003 + 2.7567\\= 39.0944

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3 years ago
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3 years ago
Be sure to answer all parts. For each of the following pairs of elements, state whether the binary compound they form is likely
andrew-mc [135]

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Nitrogen and fluorine are nonmetals, with high and similar electronegativities, so they form covalent bonds, in which they share pairs of electrons to complete the octet in their valence shell. N has 5 valence electrons so it will form 3 covalent bonds while each Cl has 7 valence electrons so it will form 1 covalent bond. As a result, the empirical formula is NF₃ (nitrogen trifluoride).

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3 0
3 years ago
Consider this reaction: 6 CO2 + 6 H2O + light equation C6H12O6 + 6 O2 If there were 2.38 x 102 g of H2O, 18.6 moles of CO2, and
alisha [4.7K]

H₂O would be the limiting reactant.

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6CO₂ + 6H₂O + light equation → C₆H₁₂O₆ + 6O₂

The amount of product that can be created is constrained by the reactant that is consumed first in a chemical reaction, commonly referred to as the limiting reactant (or limiting reagent).

Given

No. of moles of CO₂ = 18.6

Mass of H₂O = 2.38 × 10² g = 238g

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So the reactant that has less number of moles will be consumed first.

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So, H₂O is the limiting reactant with 13.22 moles.

Hence, H₂O would be the limiting reactant.

Learn more about limiting reactant here brainly.com/question/14222359

#SPJ1

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