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DENIUS [597]
2 years ago
14

Ill give brainliest if you answer right

Chemistry
2 answers:
ra1l [238]2 years ago
5 0

Answer:

God bless you!!!!!!!!!!!!!!

Paraphin [41]2 years ago
3 0

Answer:

It'll be the same as 58.44 amu. This is because of the law of conservation of mass which states that total mass of reactants is always equal to the total mass of products formed.

pls give brainliest for the answer

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How much energy is required to raise the temperature of 10.6 grams of gaseous neon from
Alona [7]

Answer:

Approximately 1.95 \times 10^{2}\; \rm J.

Explanation:

Look up the specific heat of gaseous neon:

c = 1.03 \; \rm J \cdot g^{-1} \cdot K^{-1}.

Calculate the required temperature change:

\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Let m denote the mass of a sample of specific heat C. Energy required to raise the temperature of this sample by \Delta T:

Q = c \cdot m \cdot \Delta T.

For the neon gas in this question:

  • c = 1.03\; \rm J \cdot g^{-1}\cdot K^{-1}.
  • m = 10.6\; \rm g.
  • \Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Calculate the energy associated with this temperature change:

\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^{-1}\cdot K^{-1} \times 10.6\; \rm g \times 17.9\; \rm K \\ &\approx 1.95 \times 10^{2}\; \rm J\end{aligned}.

3 0
3 years ago
What would the world be like without elements? please​
Lisa [10]

Answer:

It would be nothing. Quite literally nothing. No Oxygen, no dirt, no anything.

Explanation:

3 0
3 years ago
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What is the percent of O in CO2
zmey [24]

72.71 . simple google search, you shouldnt waste points

5 0
3 years ago
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What mass, in grams, of CO2 and H20 N<br> is formed from 2.55 mol of propane?
Black_prince [1.1K]

Answer: The mass of CO_2 and H_2O produced are 336.6 g and 183.6 g respectively.

Explanation:

The combustion reaction between propane and oxygen leads to formation of carbon dioxide and water.

Law of Conservation of mass states that the mass will remain constant for a balanced equation. This is carried out when the total number of atoms on reactant side is same as the total number of atoms on the product side. Thus the equation must be balanced.

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

a) 1 mol of propane produces = 3 moles of CO_2

Thus 2.55 mol of propane produces = \frac{3}{1}\times 2.55=7.65 moles of [tex]CO_2

mass of CO_2=moles\times {\text {molar mass}}=7.65mol\times 44g/mol=336.6g

b) 1 mol of propane produces = 4 moles of H_2O

Thus 2.55 mol of propane produces = \frac{4}{1}\times 2.55=10.2 moles of [tex]H_2O

mass of H_2O=moles\times {\text {molar mass}}=10.2mol\times 18g/mol=183.6g

The mass of CO_2 and H_2O produced are 336.6 g and 183.6 g respectively.

8 0
3 years ago
1. Es un
artcher [175]

Answer:

A ) MOVIMIENTO

Explanation:

PLEASE MARK ME AS BRAINLIEST

7 0
3 years ago
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