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MrRa [10]
3 years ago
9

In a pressure cooker, a lid is screwed tightly onto a pot so that the air pressure in the pot is increased. What effect, if any,

will this have on the boiling point of water in the pot?
The boiling point will be raised.
The boiling point will be lowered.
The boiling point will be unaffected.
None of the above.
Chemistry
2 answers:
ad-work [718]3 years ago
7 0
If a lid is screwed on tightly in a pressure cooker, the air pressure is increased. This will make the boiling point of the water to be raised. 
zmey [24]3 years ago
6 0
A liquid boils when it's vapor pressure will be equal to the atmospheric pressure. With the lid on, increases the pressure inside the pot. As an effect, it would take a higher temperature to reach the boiling temperature. 

Answer: The boiling point will be raised. <span />
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The sodium-potassium pump is called an electrogenic pump because it
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Contributes to the membrane potential.

Explanation:

Sodium-potassium pump: In cellular physiology, a protein which is identified in many cells that helping in to maintain the higher concentration of potassium ions inside than that is in the surrounding medium and maintain the lower concentration of sodium ions inside than that of the surrounding medium.

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In a chemical equation, what name does the left side have
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Read 2 more answers
A scientist measures the speed of sound in a monatomic gas to be 449 m/s at 20∘C. What is the molar mass of this gas?
Ivan

Answer:

The molar mass of the gas is 36.25 g/mol.

Explanation:

  • To solve this problem, we can use the mathematical relation:

ν = \sqrt{3RT/M}

Where, ν is the speed of light in a gas <em>(ν = 449 m/s)</em>,

R is the universal gas constant <em>(R = 8.314 J/mol.K)</em>,

T is the temperature of the gas in Kelvin <em>(T = 20 °C + 273 = 293 K)</em>,

M is the molar mass of the gas in <em>(Kg/mol)</em>.

ν = \sqrt{3RT/M}

(449 m/s) = √ (3(8.314 J/mol.K) (293 K) / M,

<em>by squaring the two sides:</em>

(449 m/s)² = (3 (8.314 J/mol.K) (293 K)) / M,

∴ M = (3 (8.314 J/mol.K) (293 K) / (449 m/s)² = 7308.006 / 201601 = 0.03625 Kg/mol.

<em>∴ The molar mass of the gas is 36.25 g/mol.</em>


7 0
3 years ago
What is the unknown metal if the temperature of a beaker of 100ml of water was raised 17c to 19 c when 21 grams of the metal at
horrorfan [7]

Answer:

The metal has a heat capacity of 0.385 J/g°C

This metal is copper.

Explanation:

<u>Step 1</u>: Data given

Mass of the metal = 21 grams

Volume of water = 100 mL

 ⇒ mass of water = density * volume = 1g/mL * 100 mL = 100 grams

Initial temperature of metal = 122.5 °C

Initial temperature of water = 17°C

Final temperature of water and the metal = 19 °C

Heat capacity of water = 4.184 J/g°C

<u />

<u>Step 2: </u>Calculate the specific heat capacity

Heat lost by the metal = heat won by water

Qmetal = -Qwater

Q = m*c*ΔT

m(metal) * c(metal) * ΔT(metal) = - m(water) * c(water) * ΔT(water)

21 grams * c(metal) *(19-122.5) = -100 * 4.184 * (19-17)

-2173.5 *c(metal) = -836.8

c(metal) = 0.385 J/g°C

The metal has a heat capacity of 0.385 J/g°C

This metal is copper.

4 0
3 years ago
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