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Tems11 [23]
3 years ago
8

A woman weighs 129 lb. If she is standing on a spring scale in an elevator that is traveling downward, but slowing up, the scale

will read:___________.
A) more than 129 lb
B) 129 lb
C) less than 129 lb
D) It is impossible to answer this question without knowing the acceleration of the elevator.
Physics
1 answer:
Lena [83]3 years ago
5 0

Answer:

C) less than 129 lb.

Explanation:

Let the elevator be slowing up with magnitude of a . That means it is accelerating downwards  with magnitude a .

If R be the reaction force

For the elevator is going downwards with acceleration a

mg - R = ma

R = mg - ma

R measures its apparent weight . Spring scale will measure his apparent weight.

So its apparent weight is less than 129 lb .

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Three small masses are positioned as follows: 2.0 kg at (0.0 m, 0.0 m), 2.0 kg at (2.0 m, 0.0 m), and 4.0 kg at (2.0 m, 1.0 m).
melamori03 [73]
Refer to the diagram shown below.

The given data is

mass, kg   Coordinates. m
-------------   -----------------
   2               (0, 0)
   2               (2, 0)
   4               (2, 1)

Total mass, M = 2+2+4 = 8kg
Let (x,y) be the coordinates of M.

Then, taking moments about the origin, we obtain
8x = 2*0 + 2*2 + 4*2 = 12
x = 1.5 m

8y = 2*0 + 2*0 + 4*1 = 4
y = 0.5 m

Answer:  (1.5, 0.5) m




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Vlada [557]

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3 years ago
A penny is dropped off the top of the Stratosphere from rest and falls freely with the
Roman55 [17]

Answer:

S = 122.5m

Explanation:

Given the following data;

Acceleration due to gravity = 9.8m/s²

Time, t = 5 seconds

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S = ut + \frac {1}{2}at^{2}

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Substituting into the equation, we have;

S = 0*5 + \frac {1}{2}*(9.8)*5^{2}

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8 0
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Which of the following statements is accurate?
Volgvan

Answer: B. If an object's velocity is changing,it's either experiencing acceleration or deceleration.


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Acceleration is a vector quantity that has both a magnitude and time.

It is represented as

Acceleration= change in velocity/time.

The SI unit for acceleration is m/s^2

8 0
3 years ago
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