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Vitek1552 [10]
2 years ago
15

Record the volume of solution that will be delivered from the pipet pictures below in units of mL

Chemistry
1 answer:
zloy xaker [14]2 years ago
7 0

Answer:

2a. 3mL.

2b. 10mL.

3. 38°C.

Explanation:

2a. We read the volume under the meniscus i.e under the curve.

The volume of the solution is 3mL.

2b. The volume of the pipette 10mL and the solution is at the calibration mark. Therefore, the volume of the solution is 10mL.

3. From the diagram given, we can see that 1 line represents 1 unit.

Now a careful look at the picture shows that the temperature is 38°C.

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If we add a catalyst to the following equation, CO + H2O + heat CO2 + H2, which way will the equilibrium shift?
Igoryamba

Answer:

No effect.

Explanation:

Hello,

In this case, considering the widely studied Le Chatelier's principle, we can realize that the factors affecting equilibrium are concentration, temperature and pressure and volume if the reaction is in gaseous phase and with non-zero change in the number of moles. In such a way, by adding a catalyst to given reaction will have no effect on the equilibrium direction.

Best regards.

7 0
3 years ago
A sample of 19 mg of 9-fluorenone is dissolved in 5 mL of diethyl ether. The resulting organic
maks197457 [2]

Answer:

15.70mg would remain

Explanation:

Partition coefficient is used to extract or purify a solute from a solvent selectively to avoid interference from other substances. For the problem, formula is:

Kp = Concentration 9-fluorenone in ether / Concentration of solute in H₂O

After the solute, 9-fluorenone, is extracted with water, the mass that remains in ether is:

(19mg - X)

<em>Where X is the mass that now is in the aqueous phase</em>

Replacing in Kp formula:

9.5 = (19mg - X) / 5mL / (X /10mL)

0.95X = 19mg - X / 5mL

4.75X = 19 - X

5.75X = 19

X = 19 / 5.75

X = 3.30mg

That means 9-fluorenone that remain in the ether layer is:

19mg - 3.30mg =

<h3>15.70mg would remain</h3>
8 0
3 years ago
Thomas has 235 grams of K2S in the chemistry lab. How many atoms of potassium (K) are in 235 grams of the compound?
iVinArrow [24]

The  number of atoms  of K that are in 235 g  of the compound  is

2.57 x10^24 atoms


 calculation

Step 1:  find the moles of K2S

= moles = mass/molar mass

=  235 g/110 g/mol= 2.136  moles

Step 2: multiply  2.136 moles  by no. of K atoms in K2S

= 2.136  x2 = 4.272 moles


Step 3: use the Avogadro's  law to determine number of K atoms

that is according to Avogadro's law  1 mole = 6.02 x 10^23  atoms

                                                            4.272 moles= ? atoms

by cross multiplication

= (4.272  moles x 6.02 x10^23 atoms)  / 1 mole = 2.57 x10^24 atoms

4 0
3 years ago
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statuscvo [17]
I believe the answer is d
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What kinds of sacrifices do governments face when considering how to reduce greenhouse gases ?
guapka [62]

Answer:

m risus ante, dapibus a ipsum dolor sit amet, add cream or a great slaughter. Fusce dui lectus, laoreet congue vel, it was said of life in hatred. Until the bananas. Lorem ipsum dolor sit amet, consectetur adipiscing elit. In fact, lacinia pulvinar dolor libero facilisis. Nutrition protein produced et. In fact, risus ante, dapibus a ipsum dolor sit amet, add cream or a great slaughter. Fusce dui lectus, laoreet congue vel, it was said of life in hatred. Until the bananas. Lorem ipsum deceit

Explanation:

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3 years ago
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