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Galina-37 [17]
3 years ago
11

Describe the motion above and answer

Physics
1 answer:
amm18123 years ago
7 0

Answer:

mmmmmmmm

Explanation:

mmmmmmmmmmmmmmmmmmmm

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The lightest car in the world was built in London and had a mass of less than 10 kg. it's maximum speed was 25.0 km/h. Suppose t
Softa [21]
25km/h = 6.94 m/s
suvat
s=16
u=6.94
v=0
a=a
v^2=u^2+2as
(v^2-u^2)/2s = a =1.5ms^-2
6 0
3 years ago
Scienctists agree that the world's climate is getting hotter. What do you think might happen as a result of this climate change?
Mama L [17]

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Bad things

Explanation:

Global warming has many terrible effects on people and the earth itself

such as, death, birth defects, asthmea, breathing conditions, increased diseases.

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3 years ago
In which of the following situations is the Doppler effect absent?
Bumek [7]
The source and the observer are moving towards each other. The observer is moving toward the source. The source is moving away from the observer
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a star has a distance of 30 parsecs and a apparent magnitude of 3 --what would its absolute magnitude be?
Alborosie

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8 0
1 year ago
A 86g ball is dropped vertically to the floor from a height of 2.87m and bounces to a height of 1.28. What is the magnitude of t
irga5000 [103]

Answer:

The impulse received by the ball from the floor during the bounce is approximately 1.11329438 m·kg/s

Explanation:

The given mass of the ball, m = 86 g = 0.089 kg

The height from which the ball is dropped, H = 2.87 m

The height to which the ball bounces, h = 1.28 m

Mathematically, we have;

Δp = F·Δt

Where;

Δp = The change in momentum = m·Δv

F = The applied force

Δt = The time of contact with the force

The velocity of the ball just before it touches the ground, v₁ = -√(2·g·H)

The velocity with which the ball leaves, v₂ = √(2·g·h)

The change in momentum, Δp = m·(v₂ - v₁)

∴ Δp = m·(√(2·g·h) - (-√(2·g·H))) = m·(√(2·g·h) +√(2·g·H) )

The impulse, Δp, received by the ball from the floor during the bounce is given as follows;

Δp = 0.089 kg × (√(2 × 9.8 m/s² × 1.28 m) + √(2 × 9.8 m/s² × 2.87 m)) ≈ 1.11329438 m·kg/s

The impulse received by the ball from the floor during the bounce, Δp ≈ 1.11329438 m·kg/s

6 0
3 years ago
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