Answer: Heat waves? I’m not %100 sure
Answer:
The source of all wave motion is a disturbance in matter or a vibration
Answer: i know that ice is denser than water because of the reason why ice is expanding:air. ice has tiny air packets inside that make it bigger than the original state(the state which a substance is at at room temperature.
Explanation:
Iron is an element that has been known in its pure form for at least 5,000 years. The name "iron" comes from the...
The element symbol for iron is Fe, which comes from the Latin word for iron, "ferrum."
Iron is one of the most plentiful elements. It comprises about 5.6 percent of the Earth's crust and almost all of its core
Iron is a transition metal.
Animals and plants require iron. Plants use iron in chlorophyll, the pigment used in photosynthesis. Humans use iron in hemoglobin molecules in blood to allow for the transport of oxygen to tissues throughout the body.
The vectors must point in the same direction.
Answer:
A. The electron will begin to move along the axis, towards the centre and the instantaneous velocity because the force acting on it depends largely on acceleration and x until it reaches maximum velocity at centre.
B. Veloctiy (Vb) = 1.66m/s
Explanation:
Given the following data
x(a) = 0.3m
x(b) = 0
q = 1.6×10^-19
Q = 24nc
r = 0.15m
Required: the motion of the electron and the velocity (Vb)
1. At point A the electron will begin to move along the axis from point A to point B, the magnitude of the electric field will change while moving which depends on that and this will produce instantaneous force which will later change and the acceleration will change too while moving, the velocity would reach maximum value at point B
2. Potential energy and kinetic energy are given by
U(a) + K(a) = U(b) + K(b). . .1
Initial P.E and K.E are given as
U(a) = kQ/√x²(a) + a2
By substitution, we have
U(a) = 9×10^9 × (-1.9×10^-19)×24×10^-9/√(0.15)²+(0.3²)
U(a) = -1.03×10^-16
Final P.E and K.E are given as
U(b) = KQ/√x²(b) + a2
By substitution, we have
U(b) = 9×10^9×(-1.9×10^-19)×24×10^-9/√(0.15)²+(0)²
U(b) = -2.3×10^16
3. By substitution into equation 1 becomes
-1.03×10^-6 - 2.3×10^-16 + MV²(b)/2
V(b) = √2×1.27×10^-16/9.1×10^31
V(b) = 1.66×10^7m/s
